Data Interpretation - Table Charts - Discussion

Discussion Forum : Table Charts - Table Chart 2 (Q.No. 3)
Directions to Solve

Study the following table and answer the questions.

Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.

State Year
1997 1998 1999 2000 2001
App.Qual. App.Qual. App.Qual. App.Qual. App.Qual.
M520072085009807400850680077595001125
N7500840920010508450920920098088001020
P64007808800102078008908750101097501250
Q8100950950012408700980970012008950995
R780087076009409800135076009457990885


3.
In which of the given years the number of candidates appeared from State P has maximum percentage of qualified candidates?
1997
1998
1999
2001
Answer: Option
Explanation:

The percentages of candidates qualified to candidates appeared from State P during different years are:

For 1997 ( 780 x 100 ) % = 12.19%.
6400

For 1998 ( 1020 x 100 ) % = 11.59%.
8800

For 1999 ( 890 x 100 ) % = 11.41%.
7800

For 2000 ( 1010 x 100 ) % = 11.54%.
8750

For 2001 ( 1250 x 100 ) % = 12.82%.
9750

Therefore Maximum percentage is for the year 2001.

Discussion:
19 comments Page 2 of 2.

Nai said:   6 years ago
I think it should be appear/qualified but why they put qualified/appear? Could anyone explain me this?
(1)

Jithin said:   9 years ago
@Tara.

It is not correct. If the denominator is also high percentage will be less.

Merina said:   1 decade ago
Is there an easier to find out the solution without doing the entire calculation??

Tara said:   9 years ago
Just see the highest figure of qualified candidates from state P in all the years.

Prabha said:   1 decade ago
Thanks praveen. The way you explained is the most simplest.

Ritesh said:   1 decade ago
@Praveen is it applicable on all similar questions.

Rudraksh Barnwal said:   8 years ago
We can solve this question by -appear/qualify*100.

S j prakash said:   9 years ago
How to calculate the percentage? Please guide me.

Patel said:   4 years ago
Very good, Thanks @Gopal.


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