Civil Engineering - Water Supply Engineering - Discussion
Discussion Forum : Water Supply Engineering - Section 3 (Q.No. 29)
29.
The ratio of maximum hourly consumption and average hourly consumption of the maximum day, is
Discussion:
31 comments Page 2 of 4.
Suraj kumar said:
4 years ago
Thanks for explaining @Priya.
ATUL KOUSHAL said:
5 years ago
B is correct. I too agree.
Dheeraj kataria said:
5 years ago
The question is totally wrong... How the ratio come 2.7?
Max. Daily demand = 1.8 of (Average daily demand)
Peak Hour consumption = 1.5 of (Max. Daily demand)
Or u can say that (1.8 * 1.5 = 2.7)
So the way that the question is asked is totally wrong.
Max. Daily demand = 1.8 of (Average daily demand)
Peak Hour consumption = 1.5 of (Max. Daily demand)
Or u can say that (1.8 * 1.5 = 2.7)
So the way that the question is asked is totally wrong.
Satyaki said:
5 years ago
The ratio of max. hourly consumption =( 2.7 LPCD /24).
The ratio of avg. hourly consumption = (1.8 LPCD /24).
So, Ans is B
The ratio of avg. hourly consumption = (1.8 LPCD /24).
So, Ans is B
Dipu said:
6 years ago
B will be the right answer.
Hassan said:
6 years ago
According to Good rich formula :
P=180 x t^-0.1.
Where t=time in days
P is in per cent.
For maximum hourly consumption t= 1/24 days,
So, P= 180 x (1/24),
= 247%.
Hence the ratio should be 2.4 and not 2.7.
Thus the correct option should be (D).
P=180 x t^-0.1.
Where t=time in days
P is in per cent.
For maximum hourly consumption t= 1/24 days,
So, P= 180 x (1/24),
= 247%.
Hence the ratio should be 2.4 and not 2.7.
Thus the correct option should be (D).
ONKAR said:
6 years ago
Given answer is correct. I agree with it.
(1)
Kartik said:
7 years ago
Thank you @Priya.
Priya said:
7 years ago
Maximum daily demand = 1.8 x average daily demand,
Maximum hourly demand of maximum day i.e. Peak demand,
= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.
Maximum hourly demand of maximum day i.e. Peak demand,
= 1.5 x average hourly demand.
= 1.5 x Maximum daily demand/24.
= 1.5 x (1.8 x average daily demand)/24.
= 2.7 x average daily demand/24.
= 2.7 x annual average hourly demand.
Satish Verma said:
7 years ago
B option is the correct answer.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers