Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 2)
2.
If the length of a transition curve to be introduced between a straight and a circular curve of radius 500 m is 90 m, the maximum deflection angle to locate its junction point, is
Discussion:
17 comments Page 1 of 2.
Armaan said:
1 decade ago
Would you like to explain it?
MAYANK said:
10 years ago
Its 90C/(pie*R) = 90*90/(pie*500) and divide it by 189 to covert into degrees = 1^43^13^.
Xyz said:
9 years ago
Can you please explain how to convert degree into degree, minutes, seconds in a scientific calculator?
RIJAZ said:
9 years ago
Please explain the answer.
Amdahl said:
9 years ago
Anyone give me the correct explanation.
Zeshan said:
8 years ago
The Maximum deflection angle of transition curve (in minutes)= (573.25*L^2)/(R*L).
Therefore = (573.25*90*90)/(500*90).
Answer = 103.18 minutes.
Convert to degrees = 1° 43' 18".
(1°= 60' ,1'= 60").
Therefore = (573.25*90*90)/(500*90).
Answer = 103.18 minutes.
Convert to degrees = 1° 43' 18".
(1°= 60' ,1'= 60").
Rajeshkumar said:
8 years ago
Option A is correct (L2/6RL) * 180/π.
Karan said:
7 years ago
Here R=90 and L= 500 is given then how can this answer is possible?
Please explain the answer in detail.
Please explain the answer in detail.
Adam basha said:
7 years ago
L2/6RL.
500^2/(6*500*90)*(180).
=1'43'7.14".
500^2/(6*500*90)*(180).
=1'43'7.14".
Shivaraj Babar said:
5 years ago
((573*90)/(500*60))=1°43'08".
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