Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 2)
2.
If the length of a transition curve to be introduced between a straight and a circular curve of radius 500 m is 90 m, the maximum deflection angle to locate its junction point, is
Discussion:
17 comments Page 1 of 2.
Roy Basak said:
4 years ago
CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
Roy Basak said:
4 years ago
CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
Abhesh kumar yadav said:
2 years ago
The maximum deflection angle of a transition curve is given by the formula:
δ = L^2/6RL.
where:
L is the length of the transition curve.
R is the radius of the circular curve.
l is the length of the tangent.
In this case, L = 90 m and R = 500 m, so the maximum deflection angle is:
δ = 90^2 / 6 * 500 * 90 = 1°43'08".
Therefore, the correct answer is 1°43'08".
δ = L^2/6RL.
where:
L is the length of the transition curve.
R is the radius of the circular curve.
l is the length of the tangent.
In this case, L = 90 m and R = 500 m, so the maximum deflection angle is:
δ = 90^2 / 6 * 500 * 90 = 1°43'08".
Therefore, the correct answer is 1°43'08".
(5)
Zeshan said:
8 years ago
The Maximum deflection angle of transition curve (in minutes)= (573.25*L^2)/(R*L).
Therefore = (573.25*90*90)/(500*90).
Answer = 103.18 minutes.
Convert to degrees = 1° 43' 18".
(1°= 60' ,1'= 60").
Therefore = (573.25*90*90)/(500*90).
Answer = 103.18 minutes.
Convert to degrees = 1° 43' 18".
(1°= 60' ,1'= 60").
Bishnu bhul said:
7 months ago
Here
Given data
- Radius of circular curve (R) = 500m
- Length of transition curve(L) = 90m
- maximum deflection angle (X) = ?
From formulae;
X = (L^2/6RL)*180/ π.
X = (90*90)/(6*500*90)*180/ π.
Given data
- Radius of circular curve (R) = 500m
- Length of transition curve(L) = 90m
- maximum deflection angle (X) = ?
From formulae;
X = (L^2/6RL)*180/ π.
X = (90*90)/(6*500*90)*180/ π.
Karan said:
7 years ago
Here R=90 and L= 500 is given then how can this answer is possible?
Please explain the answer in detail.
Please explain the answer in detail.
Xyz said:
9 years ago
Can you please explain how to convert degree into degree, minutes, seconds in a scientific calculator?
MAYANK said:
10 years ago
Its 90C/(pie*R) = 90*90/(pie*500) and divide it by 189 to covert into degrees = 1^43^13^.
Adam basha said:
7 years ago
L2/6RL.
500^2/(6*500*90)*(180).
=1'43'7.14".
500^2/(6*500*90)*(180).
=1'43'7.14".
Rajeshkumar said:
8 years ago
Option A is correct (L2/6RL) * 180/π.
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