# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 6 (Q.No. 2)
2.
If the length of a transition curve to be introduced between a straight and a circular curve of radius 500 m is 90 m, the maximum deflection angle to locate its junction point, is
1°43' 08"
1°43' 18"
1°43' 28"
1°43' 38"
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

John said:   2 years ago
The correct answer is option A.

Roy Basak said:   2 years ago
CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook

Explanation:

Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.

(For those asking where the 573 in the above explanations came from its simply 180/π =573).

Roy Basak said:   2 years ago
CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook

Explanation:

Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.

(For those asking where the 573 in the above explanations came from its simply 180/π =573).

Dawood khan said:   2 years ago
@Zeshan.

How come 573.25?

ER.MUSKAN said:   2 years ago
LENGTH OF CURVE= π * R * D/180.
(1)

Shivaraj Babar said:   3 years ago
((573*90)/(500*60))=1°43'08".

Adam basha said:   4 years ago
L2/6RL.
500^2/(6*500*90)*(180).
=1'43'7.14".

Karan said:   5 years ago
Here R=90 and L= 500 is given then how can this answer is possible?

Rajeshkumar said:   6 years ago
Option A is correct (L2/6RL) * 180/π.

Zeshan said:   6 years ago
The Maximum deflection angle of transition curve (in minutes)= (573.25*L^2)/(R*L).
Therefore = (573.25*90*90)/(500*90).