# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 6 (Q.No. 2)

2.

If the length of a transition curve to be introduced between a straight and a circular curve of radius 500 m is 90 m, the maximum deflection angle to locate its junction point, is

Discussion:

16 comments Page 1 of 2.
Abhesh kumar yadav said:
9 months ago

The maximum deflection angle of a transition curve is given by the formula:

δ = L^2/6RL.

where:

L is the length of the transition curve.

R is the radius of the circular curve.

l is the length of the tangent.

In this case, L = 90 m and R = 500 m, so the maximum deflection angle is:

δ = 90^2 / 6 * 500 * 90 = 1°43'08".

Therefore, the correct answer is 1°43'08".

δ = L^2/6RL.

where:

L is the length of the transition curve.

R is the radius of the circular curve.

l is the length of the tangent.

In this case, L = 90 m and R = 500 m, so the maximum deflection angle is:

δ = 90^2 / 6 * 500 * 90 = 1°43'08".

Therefore, the correct answer is 1°43'08".

(1)

John said:
2 years ago

The correct answer is option A.

(2)

Roy Basak said:
3 years ago

CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook

Explanation:

Max Deflection angle = L^2/6RL (this is in radians),

So in degrees, it will be =L ^2/6RL [180/π],

In minutes it will be = 1800 [L^2/RL].

Thus applying this formula we get max Deflection angle = 1°43"08'.

(For those asking where the 573 in the above explanations came from its simply 180/π =573).

Explanation:

Max Deflection angle = L^2/6RL (this is in radians),

So in degrees, it will be =L ^2/6RL [180/π],

In minutes it will be = 1800 [L^2/RL].

Thus applying this formula we get max Deflection angle = 1°43"08'.

(For those asking where the 573 in the above explanations came from its simply 180/π =573).

Roy Basak said:
3 years ago

CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook

Explanation:

Max Deflection angle = L^2/6RL (this is in radians),

So in degrees, it will be =L ^2/6RL [180/π],

In minutes it will be = 1800 [L^2/RL].

Thus applying this formula we get max Deflection angle = 1°43"08'.

(For those asking where the 573 in the above explanations came from its simply 180/π =573).

Explanation:

Max Deflection angle = L^2/6RL (this is in radians),

So in degrees, it will be =L ^2/6RL [180/π],

In minutes it will be = 1800 [L^2/RL].

Thus applying this formula we get max Deflection angle = 1°43"08'.

(For those asking where the 573 in the above explanations came from its simply 180/π =573).

Dawood khan said:
3 years ago

@Zeshan.

How come 573.25?

How come 573.25?

ER.MUSKAN said:
3 years ago

LENGTH OF CURVE= π * R * D/180.

(1)

Shivaraj Babar said:
4 years ago

((573*90)/(500*60))=1°43'08".

Adam basha said:
5 years ago

L2/6RL.

500^2/(6*500*90)*(180).

=1'43'7.14".

500^2/(6*500*90)*(180).

=1'43'7.14".

Karan said:
6 years ago

Here R=90 and L= 500 is given then how can this answer is possible?

Please explain the answer in detail.

Please explain the answer in detail.

Rajeshkumar said:
7 years ago

Option A is correct (L2/6RL) * 180/π.

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