Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 2)
2.
If the length of a transition curve to be introduced between a straight and a circular curve of radius 500 m is 90 m, the maximum deflection angle to locate its junction point, is
Discussion:
17 comments Page 2 of 2.
ER.MUSKAN said:
5 years ago
LENGTH OF CURVE= π * R * D/180.
(1)
Dawood khan said:
5 years ago
@Zeshan.
How come 573.25?
How come 573.25?
Roy Basak said:
4 years ago
CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
Roy Basak said:
4 years ago
CORRECT ANSWER IS A - 1°43"08' -Cofirmed from textbook
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
Explanation:
Max Deflection angle = L^2/6RL (this is in radians),
So in degrees, it will be =L ^2/6RL [180/π],
In minutes it will be = 1800 [L^2/RL].
Thus applying this formula we get max Deflection angle = 1°43"08'.
(For those asking where the 573 in the above explanations came from its simply 180/π =573).
John said:
4 years ago
The correct answer is option A.
(2)
Abhesh kumar yadav said:
2 years ago
The maximum deflection angle of a transition curve is given by the formula:
δ = L^2/6RL.
where:
L is the length of the transition curve.
R is the radius of the circular curve.
l is the length of the tangent.
In this case, L = 90 m and R = 500 m, so the maximum deflection angle is:
δ = 90^2 / 6 * 500 * 90 = 1°43'08".
Therefore, the correct answer is 1°43'08".
δ = L^2/6RL.
where:
L is the length of the transition curve.
R is the radius of the circular curve.
l is the length of the tangent.
In this case, L = 90 m and R = 500 m, so the maximum deflection angle is:
δ = 90^2 / 6 * 500 * 90 = 1°43'08".
Therefore, the correct answer is 1°43'08".
(5)
Bishnu bhul said:
7 months ago
Here
Given data
- Radius of circular curve (R) = 500m
- Length of transition curve(L) = 90m
- maximum deflection angle (X) = ?
From formulae;
X = (L^2/6RL)*180/ π.
X = (90*90)/(6*500*90)*180/ π.
Given data
- Radius of circular curve (R) = 500m
- Length of transition curve(L) = 90m
- maximum deflection angle (X) = ?
From formulae;
X = (L^2/6RL)*180/ π.
X = (90*90)/(6*500*90)*180/ π.
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