# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 2 (Q.No. 24)

24.

A tape of length

*l*and weight*W*kg/m is suspended at its ends with a pull of*P*kg, the sag correction isDiscussion:

31 comments Page 1 of 4.
Raya said:
2 years ago

{L(WxW)}/{24(nxn)(PxP)}.

Madan said:
2 years ago

Agree, A is the correct answer.

GIRIJA PRASAD said:
4 years ago

Option A is the right answer.

As w is given in kg / m then the above formula is correct.

But the formula will change whenever W becomes TOTAL WEIGHT. Then the formula.

= (W^2*L) Ã· 24p^2.

As w is given in kg / m then the above formula is correct.

But the formula will change whenever W becomes TOTAL WEIGHT. Then the formula.

= (W^2*L) Ã· 24p^2.

Lohith GC said:
4 years ago

The Correct answer is W^2L/24P^2.

Gokul said:
5 years ago

W=udl.

So, W=wl,

= l*(wl)^2/24p^2.

sag correction = l^3w^2/ 24p^2.

So, W=wl,

= l*(wl)^2/24p^2.

sag correction = l^3w^2/ 24p^2.

(3)

Orack said:
6 years ago

Answer A is correct because weight is taken as w kg/m length of tape.

So W=wl.

Correction for sag is l/24*(W/P)^2.

l/24*(wl/P)^2.

So W=wl.

Correction for sag is l/24*(W/P)^2.

l/24*(wl/P)^2.

Kibs said:
6 years ago

Sag correction = L(W)^2/24(P)^2.

Chaugule B M said:
6 years ago

Sag correction = W^2l/24p^2.

Prashanth said:
6 years ago

Correction due to sag (same in levels).

C = w^2 * l/24 * n^2 * p^2.

Where,

W- Total weight of the chain,

n- Number of supports.

If 1 support n=2.

If 2 support n=3.

Correction due to sag (Different levels).

C = Csag*cos^2 &teeta;

C = w^2 * l/24 * n^2 * p^2.

Where,

W- Total weight of the chain,

n- Number of supports.

If 1 support n=2.

If 2 support n=3.

Correction due to sag (Different levels).

C = Csag*cos^2 &teeta;

Nouman khan said:
6 years ago

From know source formula of sag correction is = lw^2/24p^2.

The weight here is w/m while in formula its w only thus;

SAG correction = l(w*l)^2/24p^2 ( To cancel meters of weight).

Thus option A is right.

The weight here is w/m while in formula its w only thus;

SAG correction = l(w*l)^2/24p^2 ( To cancel meters of weight).

Thus option A is right.

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