Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 2 (Q.No. 24)
24.
A tape of length l and weight W kg/m is suspended at its ends with a pull of P kg, the sag correction is
.Discussion:
31 comments Page 1 of 4.
Chandradeep said:
10 years ago
Its lw^2/24p^2.
PARITOSH MAHATO said:
10 years ago
Here W = unit wt of tape.
Rishabh said:
9 years ago
All the options given here are incorrect.
The formula for sag correction is,
(L/24) * (W/P)^2.
The formula for sag correction is,
(L/24) * (W/P)^2.
Ganesh rajgure said:
9 years ago
As per my knowledge, it is w^2l^2/24P^2.
Vatsal said:
9 years ago
Option A is right answer.
(L/24) * (WL/P)^2.
(L/24) * (WL/P)^2.
Baloch said:
9 years ago
I think its l^2 (not 3).
Correct me, If I am wrong.
Correct me, If I am wrong.
Annie said:
9 years ago
Yes, you are right @Vatsal.
Bhupendra murariya said:
9 years ago
Sag correction formula (WL)^2/(24P)^2.
Abhishek Anand said:
9 years ago
Ans must be, Cs= - (w^2)*(L^3)/24(P^2) for sag correction. If the tape is standarized in catenary, But it used flat in the field the sag correction is +'ve.
Navya said:
8 years ago
The correct answer is 1/24 (W/P) L.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers