Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 2 (Q.No. 24)
24.
A tape of length l and weight W kg/m is suspended at its ends with a pull of P kg, the sag correction is
.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
31 comments Page 2 of 4.

Pawar.ce said:   7 years ago
@All.

The Formula for correction for sag is= (w^2L^3)/24P^2.
Where w= weight of the tape in N/m.

And
w=W/L.
where W= weight of the tape in N.
Therefore above formula can also be written as;
Correction= (W^L)/24P^2.

Sachin said:   7 years ago
It's is W^2l/24p^2.

Anuj kumar said:   7 years ago
It is w^2l^2/24p^2.

Jyoti Bhatia said:   7 years ago
@Kaweri and @Vishal.

You both are correct. The correct answer is w^2L^2/24P^2.

Vishal said:   7 years ago
It is W^2l^2/24p^2.

Sarvesh Prajapati said:   8 years ago
Here -> (L*w2)÷(24p2).

Aitizaz Afser said:   8 years ago
L x (mg x l ) *2/ 24p*2 is original formula.

Reference book TP Kanetkar page 13.

Mg is equal to W so L*3 W*2/ 24P*2 is the answer.

Harsh said:   8 years ago
A is correct.
W is udl,
W=wl.

KAWERI kulat said:   8 years ago
I think formula is w2l2/24p2 not l3.

Gaurang chauhan said:   8 years ago
I think the option D is the correct answer.

(refer: surveying volume 1 by b.c. Punamiya page 62 correction for sag tie in linear measurement).


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