Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 3)
3.
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
Discussion:
42 comments Page 1 of 5.
Tamene malke said:
2 years ago
It is very good for all engineering students, thanks to everyone for explaining.
(3)
Vamsiambati said:
3 years ago
(T hollow/T shaft)=(D^4-d^4)/D^4.
Here D= Diameter of Solid Shaft.
d=Diameter of Hollow Shaft = D/2.
(D^4-(D/2)^4)/D^4 =15/16.
Here D= Diameter of Solid Shaft.
d=Diameter of Hollow Shaft = D/2.
(D^4-(D/2)^4)/D^4 =15/16.
(6)
Chivi said:
3 years ago
@All.
It's 15/16.
It's 15/16.
(2)
RAJVIR SINGH said:
3 years ago
16/15.
(1)
BOSS said:
4 years ago
Therefore the torsion = th/ts.
Th=15, ts=16.
Hence, torsion (t) =th/ts=15/16.
Th=15, ts=16.
Hence, torsion (t) =th/ts=15/16.
(2)
Parth said:
4 years ago
@All.
The question is ratio of the solid shaft to the hollow shaft not hollow shaft to solid shaft.
So the answer will be : 16/15.
The question is ratio of the solid shaft to the hollow shaft not hollow shaft to solid shaft.
So the answer will be : 16/15.
(2)
Bikalp said:
5 years ago
The Answer should be 16/15.
(1)
Pratyush said:
5 years ago
Here torsion of solid shaft/torsion of the hollow shaft.
Ts/Th =16/15.
Ts/Th =16/15.
(1)
Deepak kumar said:
5 years ago
Th/Ts=(D^4-d^4)/D*Ds^3,
Ds is diameter of solid shaft,
put d=D/2,
we get 15/16,
Ds is diameter of solid shaft,
put d=D/2,
we get 15/16,
Abidha karthu said:
5 years ago
Yes, the ratio of solid to hollow will be 16/15.
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