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Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 3)
Strength of Materials
3.
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
1/4
1/2
1/16
15/16
3/8
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
42 comments Page 1 of 5.
Vamsiambati said:   4 years ago
(T hollow/T shaft)=(D^4-d^4)/D^4.

Here D= Diameter of Solid Shaft.

d=Diameter of Hollow Shaft = D/2.
(D^4-(D/2)^4)/D^4 =15/16.
(8)
Tamene malke said:   3 years ago
It is very good for all engineering students, thanks to everyone for explaining.
(3)
BOSS said:   4 years ago
Therefore the torsion = th/ts.

Th=15, ts=16.
Hence, torsion (t) =th/ts=15/16.
(3)
Parth said:   5 years ago
@All.

The question is ratio of the solid shaft to the hollow shaft not hollow shaft to solid shaft.

So the answer will be : 16/15.
(3)
Chivi said:   4 years ago
@All.

It's 15/16.
(2)
RAJVIR SINGH said:   4 years ago
16/15.
(2)
Bikalp said:   5 years ago
The Answer should be 16/15.
(2)
Pratyush said:   5 years ago
Here torsion of solid shaft/torsion of the hollow shaft.
Ts/Th =16/15.
(2)
Salman said:   8 years ago
Shear stress= 16T/πD3(solid).

Shear stress=16T/πD3(1-d4/D4)
=16T/π(D4-d4)/D
=16T/π/(15D4/16)/D
=16*16T/(π*15*D3)
Ratio=16T/πD3:16*16T/15πD3.
= 15/16.
(1)
Raju Katara said:   9 years ago
A hollow steel shaft of 300 mm external diameter and 200 mm internal diameter has to be replaced by a solid steel shaft of 300 mm external diameter and 200 mm internal diameter has to be replaced by a solid steel shaft of?

Give me the answer.
(1)
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