Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 3)
3.
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
Discussion:
42 comments Page 5 of 5.
Avinash said:
1 decade ago
max stress = Tymax/Ip; where Ip = polar moment of inertia.
ymax = D/2.
max stress(solid) = 16T/piD^3.
max stress(hollow) = 32T(D/2)/pi(D^4-d^4).
Replacing d = D/2.
The ratio we get is 15/16.
ymax = D/2.
max stress(solid) = 16T/piD^3.
max stress(hollow) = 32T(D/2)/pi(D^4-d^4).
Replacing d = D/2.
The ratio we get is 15/16.
Maggie said:
1 decade ago
The strength of a solid shaft in torsion is given by,
T(solid shaft) = (pi/16)*(max stres)*(D^3).
T(hollow shaft) = (pi/16)*(max stres)*(D^4-d^4)/D.
On solving we get 15/16.
T(solid shaft) = (pi/16)*(max stres)*(D^3).
T(hollow shaft) = (pi/16)*(max stres)*(D^4-d^4)/D.
On solving we get 15/16.
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