Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 3)
3.
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
Discussion:
42 comments Page 2 of 5.
Prachi said:
6 years ago
Yes, it is 16/15 because it has asked for the ratio of solid to the hollow shaft.
(1)
SANTOSH said:
6 years ago
It is 16/15.
Basavaraj said:
6 years ago
I think we get 16/15.
Ekon said:
7 years ago
Answer should be 16/15. If the answer is 15/16 then it is implying that the hollow shaft is stronger than the solid shaft of same outer diameter, which is not correct.
Azzu said:
7 years ago
Strength proportional to section modulus,
So, I got 16/15.
So, I got 16/15.
NeeL said:
8 years ago
Ration obtain is 16/15.
ABDUL SOVAN KHAN said:
8 years ago
((π/16)*maximum shere stress*(outside dia)^3)/((π/16)*maximum shere stress*((out side dia^4-inside dia^4)/inside dia)=16D^4/15D^4=16/15.
Nitish said:
8 years ago
(1-k^4).
K= d/2÷D,
d/2=.5
Ans .937.
K= d/2÷D,
d/2=.5
Ans .937.
Gangadhar said:
8 years ago
Simply says (1-(1^4÷2÷4)=15÷16.
Salman said:
8 years ago
Shear stress= 16T/πD3(solid).
Shear stress=16T/πD3(1-d4/D4)
=16T/π(D4-d4)/D
=16T/π/(15D4/16)/D
=16*16T/(π*15*D3)
Ratio=16T/πD3:16*16T/15πD3.
= 15/16.
Shear stress=16T/πD3(1-d4/D4)
=16T/π(D4-d4)/D
=16T/π/(15D4/16)/D
=16*16T/(π*15*D3)
Ratio=16T/πD3:16*16T/15πD3.
= 15/16.
(1)
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