Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 28)
28.
For a given material Young's modulus is 200 GN/m2 and modulus of rigidity is 80 GN/m2. The value of Poisson's ratio is
0.15
0.20
0.25
0.30
0.40
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
24 comments Page 2 of 3.

Ammulu said:   9 years ago
E = 2g(1 + u),
200 = 2 * 80(1 + u),
200 = 160 + 160u,
U = -40 ÷ 160,
U = 1 ÷ 4,
U = 0.25.

Abigail said:   9 years ago
I tried d formulae for the relationship between bulk modulus and modulus of rigidity but it's not giving me the right answer.

Can anyone help me?

Anusha Reddy said:   8 years ago
Good explanation @Ammulu.

Bikash kabiraj said:   8 years ago
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].
e = 3k(1-2/m)=2c(1+1/m)=9kc/3k+c,
e = 200 and c=80.
e = 2c(1+1/m) so 200=2*80(1+1/m) so 1/m=40 /160 =. 25ans.

Gondelamahesh said:   8 years ago
If the modulus of rigidity is 80 kn/mm square and bulk modulus 140 kn/mm square position ratio is what anyone explain it?

Shruti said:   8 years ago
E = 2G( 1+U),
200= 2 * 80( 1+U),
200/160 = (1+U),
5/4-= (1+U),
5 = 4(1+U)5=4+4U,
4U = 5-4,
u= 1/4 = 0.25.
(1)

Chakradhar padhan said:   8 years ago
Relation between e[young], k[bulk], c[mod of rig] and 1/m[poiss].e = 3k(1-2/m)=2c(1+1/m)
=9kc/3k+c,e = 200 and c=80.e = 2c(1+1/m).
So 200=2*80(1+1/m) so 1/m=40 /160 =. 25.

Pradip behera said:   8 years ago
Here, E=2G(1+u)=3K(1-2u)=9KG/(3K+G).

Akshata said:   7 years ago
1st find Youngs Modulus (E) using E= (9KG)/(G+3K) where K=bulk modulus & G= modulus of rigidity then E=2G (1+u) where u= Poisson's ratio.
(1)

Viru kapoor said:   7 years ago
E=2G(1+U).
Given E=200.
G=80.

200=2 * 80(1+u).
200/2 * 80=1+u,
1.25=1+u,
u=1.25 - 1=0.25.
(1)


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