Civil Engineering - Steel Structure Design - Discussion
Discussion Forum : Steel Structure Design - Section 1 (Q.No. 5)
5.
If the pitch is 6 cm and rivet value is 4 tonnes, the number of rivets required for a riveted connection carrying an eccentric load of 15 tonnes at a distance of 30 cm from the centre line, is
Discussion:
19 comments Page 2 of 2.
Pramit Samanta said:
4 years ago
The number of rivet lines is not provided. Then how to predict?
(3)
Deepanshu said:
1 decade ago
(6M/lpR)^1/2.
(6x30x15/2x6x4)^1/2.
7.5 answer.
8 rivet.
(6x30x15/2x6x4)^1/2.
7.5 answer.
8 rivet.
(1)
Agni said:
9 years ago
What is the formula for strength in shearing and bearing?
Siraj said:
6 years ago
@Asif Bhai, amazed with your explanation. :).
Jayapriya said:
5 years ago
Thank you all for giving the explanation.
Saurabh pal said:
9 years ago
According to me,
Mri/(nri2) + p.
n = 15
Mri/(nri2) + p.
n = 15
Sintu Paul said:
8 years ago
@Deepanshu.
How I = 2? Explain.
How I = 2? Explain.
Sejal said:
8 years ago
What is the value of s?
(1)
Vina said:
4 years ago
N = (6m/rv)^.5.
(1)
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