Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
Discussion:
123 comments Page 11 of 13.
Chandu said:
6 years ago
The correct Answer is 50.1.
Avnit said:
6 years ago
Flow index = (70-20)/log(100/10) = 50.
50 = (W-20)/log(100/25).
Therefore W = 50.
50 = (W-20)/log(100/25).
Therefore W = 50.
Md. Suruzzaman said:
6 years ago
The water content at which soil changes from liquid limit to plastic limit is called liquid limit.
Prasantambc said:
6 years ago
70% correspond.
Linear rules:- 70-(((70-20)/(10-100))*(10-25)),
=70-8.33,
= 62.67.
Linear rules:- 70-(((70-20)/(10-100))*(10-25)),
=70-8.33,
= 62.67.
Pintu kumar(Govt.poly saharsa,bihar said:
6 years ago
Given,
n1=10, w1=70%.
n2=100, w2=20%.
liquid limit(1) = 70*(100÷25)^.121 = 82.78.
liquid limit(2) = 20*(10÷25)^.121 = 17.90.
Total = (82.78-17.90) = 65%.
Ans 65%.
n1=10, w1=70%.
n2=100, w2=20%.
liquid limit(1) = 70*(100÷25)^.121 = 82.78.
liquid limit(2) = 20*(10÷25)^.121 = 17.90.
Total = (82.78-17.90) = 65%.
Ans 65%.
(2)
Hardik said:
6 years ago
How to find 4^0.12 without a calculator?
(1)
Biniam said:
6 years ago
Using interpolation the liquid limit at 25 no of blow is 61.67%.
Asutosh said:
6 years ago
Liquid Limit= W * (N/25)^0.121.
Where,
W = Water content at N blows.
N = No.of blows.
Liquid limit = 70*(10/25)^0121 = 89.55%.
Liquid Limit = 20*(100/25)^0.121 = 23.65%.
Required liquid limit = 88-23 = 65%.
Where,
W = Water content at N blows.
N = No.of blows.
Liquid limit = 70*(10/25)^0121 = 89.55%.
Liquid Limit = 20*(100/25)^0.121 = 23.65%.
Required liquid limit = 88-23 = 65%.
Raysz said:
6 years ago
(70/20)/(10-100) = (70-W)/(10-25).
W = 61.67.
W = 61.67.
Majid said:
5 years ago
=70-50/(log100-log10)*(log25-log10).
~~ 50%.
~~ 50%.
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