Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
Discussion:
123 comments Page 10 of 13.
Navya said:
6 years ago
Interpolation method is correct method for liquid limit at 25 blows. So the answer is 50%.
Anoni said:
6 years ago
Thank you @Akash.
Rahi said:
6 years ago
70x(10/25)^0.121 = 62.65378306.
Am I right? Thanks.
Am I right? Thanks.
Khushi said:
6 years ago
How come 0 .121? Please explain.
Abdul Quader said:
6 years ago
N1=10, W1=70% & N2=100, W2=20%.
WL1 = W1*(N1/25)^0.121 = 70*(10/25)^0.121 = 62.65%,
WL2 = W2*(N2/25)^0.121 = 20*(100/25)^0.121 = 23.65,
Required Liquid Limit= WL1 - WL2.
= 62.65 - 23.65,
= 39%.
So, Answer (D) None of These.
WL1 = W1*(N1/25)^0.121 = 70*(10/25)^0.121 = 62.65%,
WL2 = W2*(N2/25)^0.121 = 20*(100/25)^0.121 = 23.65,
Required Liquid Limit= WL1 - WL2.
= 62.65 - 23.65,
= 39%.
So, Answer (D) None of These.
(1)
Kishan said:
6 years ago
The correct answer is 50%, because we can't apply interpolation to a semilog graph, so need to solve using flow index.
Shubham said:
6 years ago
By interpolation, the correct answer is 50%.
Faruque Abdullah said:
6 years ago
tanβ = 0.121 is for the range of 20 to 30 blows.
As the blows number is out of this range this value should be adjusted for the individual case.
For 20 to 30 blows, tanβ = 20/(30^1.5) = 0.121.
Case-I:
tanβ = 10/(25^1.5)=0.08.
w(LL) = 70 x (10/25)^0.08 = 65.05 which is tends to 65%.
Case-II:
tanβ = 100/(25^1.5) = 0.8.
w(LL) = 20 x (100/25)^0.08 = 60.62 which is close to 65%.
As the blows number is out of this range this value should be adjusted for the individual case.
For 20 to 30 blows, tanβ = 20/(30^1.5) = 0.121.
Case-I:
tanβ = 10/(25^1.5)=0.08.
w(LL) = 70 x (10/25)^0.08 = 65.05 which is tends to 65%.
Case-II:
tanβ = 100/(25^1.5) = 0.8.
w(LL) = 20 x (100/25)^0.08 = 60.62 which is close to 65%.
KickTony said:
6 years ago
Do iteration, with N=25 blows=x.
(x1,y1) = (10,70),
(x2,y2) = (100,20),
(x,y) = (25,LL).
Substitute the values in below equation.
(y2-y1)/(x2-x1)=(y-y1)/(x-x1).
LL=65.
(x1,y1) = (10,70),
(x2,y2) = (100,20),
(x,y) = (25,LL).
Substitute the values in below equation.
(y2-y1)/(x2-x1)=(y-y1)/(x-x1).
LL=65.
Rahul said:
6 years ago
Go flow index or similarities of traingle and the answer is 50.1.
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