Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
Discussion:
123 comments Page 13 of 13.
Vivek said:
3 years ago
Using the formula of one point method.
WL= Wn(N/25)^0.1.
Where N should be between 15 to 35.
Using nearest value from data i.e. N=10 & Wn = 70.
WL = 0.70 * (10/25)^0.1 = 0.6387~0.65 ans.
WL= Wn(N/25)^0.1.
Where N should be between 15 to 35.
Using nearest value from data i.e. N=10 & Wn = 70.
WL = 0.70 * (10/25)^0.1 = 0.6387~0.65 ans.
(26)
Yashasvi Vishwakarma said:
2 years ago
Flow index = water content at 10 no of blows - water content at 100 no of blows.
So, flow index = W10-W100 = 70-20 = 50%.
So, flow index = W10-W100 = 70-20 = 50%.
(12)
DaKiht said:
1 year ago
@All.
Here, we don't use the Empirical formula i.e- WL=WP*(N/25)^x [where x = 0.1-0.3] the value of x is not given in the question.
The Main formula is preferred over the empirical.
Flow Index (If) = (w1-w2)/log(N2/N1) = (70-20)/log(100/10) = 50.
The same formula was used to find moisture content at 25 No. of blows is 50%.
If = (w1-w2)/log(N2/N1),
50 = (w1-20)/log(100/25),
w1 = 50%.
Here, we don't use the Empirical formula i.e- WL=WP*(N/25)^x [where x = 0.1-0.3] the value of x is not given in the question.
The Main formula is preferred over the empirical.
Flow Index (If) = (w1-w2)/log(N2/N1) = (70-20)/log(100/10) = 50.
The same formula was used to find moisture content at 25 No. of blows is 50%.
If = (w1-w2)/log(N2/N1),
50 = (w1-20)/log(100/25),
w1 = 50%.
(8)
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