Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
Discussion:
123 comments Page 12 of 13.
Anandhu Satheesan said:
5 years ago
(25-10)÷(100-25) = (X-70) ÷ (20-X),
After interpolate X = 61.66%.
After interpolate X = 61.66%.
Tanmoy das said:
5 years ago
Liquid Limit = W*(N/25)^0.121.
Where,
W = water content at N blow.
N = number of the blow.
Liquid Limit = 70*(10/25)^0.121 =89.55%.
Liquid Limit = 20*(100/25)^ 0.121 = 23.65%.
Required Liquid Limit = ( 88-23) = 65%.
Where,
W = water content at N blow.
N = number of the blow.
Liquid Limit = 70*(10/25)^0.121 =89.55%.
Liquid Limit = 20*(100/25)^ 0.121 = 23.65%.
Required Liquid Limit = ( 88-23) = 65%.
(12)
Niva said:
5 years ago
Liquid limit-water content by soil with small shear strength.
(3)
Sneha Mathai said:
5 years ago
Take log(no of blows) only for finding flow index or for finding liquid limit using a flow index value.
If the graph is given and we want to find LL, then just do interpolate without taking the log of no of blows. Because we are plotting as such in semilog to get a straight line.
ie, (70-20)/(100-10) = (LL-20)/(100-25).
LL = 61.66.
If the graph is given and we want to find LL, then just do interpolate without taking the log of no of blows. Because we are plotting as such in semilog to get a straight line.
ie, (70-20)/(100-10) = (LL-20)/(100-25).
LL = 61.66.
(7)
Hareram sah said:
5 years ago
The formula of liquid limit =w* (N/25) ^0.121.
Find, LL for each condition and then subtract them. You will get 65% as answer.
Find, LL for each condition and then subtract them. You will get 65% as answer.
(14)
Manjusha Shinde said:
4 years ago
LL = w*(N/25)^0.121.
LL = 70*(100/25)^0.121 = 82.78%.
LL = 20*(10/25)^0.121 = 17.90%.
LL = 83 - 18 = 65%.
LL = 70*(100/25)^0.121 = 82.78%.
LL = 20*(10/25)^0.121 = 17.90%.
LL = 83 - 18 = 65%.
(47)
Noblen said:
4 years ago
50.10 is the correct answer.
It is not a triangle so don't use similar triangles. it is a logarithmic function. interpolate it using ln.
It is not a triangle so don't use similar triangles. it is a logarithmic function. interpolate it using ln.
(4)
Dikesh don said:
4 years ago
The correct answer is B) 50%.
(11)
Haseeb said:
4 years ago
The Correct Answer is 50%. Flow Index is 50. Flow Index = (w1-w2)/log(N2/N1) = (70-20)/log(100/10) = 50.
Now, using that Flow Index of 50 and the same formula to find moisture content at 25 No. of blows is 50%.
Flow Index = (w1-w2)/log(N2/N1),
50 = (w1-20)/log(100/25),
w1 = 50.1%.
Now, using that Flow Index of 50 and the same formula to find moisture content at 25 No. of blows is 50%.
Flow Index = (w1-w2)/log(N2/N1),
50 = (w1-20)/log(100/25),
w1 = 50.1%.
(19)
Neeraj Bhandari said:
4 years ago
According to me, the solution is;
10 -> 70%.
100 -> 20%.
25 -> ?.
Ans = [(70-20)/log (100/10)] * log25.
= 50*log25.
= 69.9.
10 -> 70%.
100 -> 20%.
25 -> ?.
Ans = [(70-20)/log (100/10)] * log25.
= 50*log25.
= 69.9.
(16)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers