Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
Discussion:
123 comments Page 1 of 13.
Ashirwad said:
1 decade ago
Liquid limit is defined as the moisture content at which a groove made in a pat of soil will flow through a distance of 13mm under an impact of 25 blows. Using linear interpolation with the help of flow curve we can get the above.
Pratima Yadav said:
1 decade ago
Liquid Limit= W * (N/25)^0.121.
where,
W= water content at N blows.
N= no.of blows.
where,
W= water content at N blows.
N= no.of blows.
Apoorv said:
1 decade ago
We can find the flow index 1st using.
I = (w1 - w2)/log(n2/n1) and then find the water content corresponding to the 25 blows using this flow index value.
I = (w1 - w2)/log(n2/n1) and then find the water content corresponding to the 25 blows using this flow index value.
Ravi Verma said:
1 decade ago
Just simply apply interpolation with 25 blows.
ASHISH WAGHMARE said:
1 decade ago
STEP1: just draw the rough graph on which, no. of blows on X-axis and moisture content on Y-axis.
80%.
M C 70%. .A(10,70%)
O O 60%.
I N 50%.
S T 40%.
T E 30%.
U N 20%. .B(100,20%)
R T 10%.
E(%)0% . . . . . . . . . . . .
0 10 20 30 40 50 60 70 80 90 100 110
NO. OF BLOWS
STEP2: Join the coordinates A and B.
STEP3: draw the vertical line from 25 no. of blows to the line AB and mark it.
STEP4: Draw horizontal line from the marked point on line AB To the pt. on Y-axis, that same will give us the liquid limit of soil sample(ie. 65%).
(NOTE: ALL STEPS ARE TAKEN FROM EXPERIMENT OF DETERMINATION OF LIQUID LIMIT BY USING LIQUID LIMIT DEVICE)
80%.
M C 70%. .A(10,70%)
O O 60%.
I N 50%.
S T 40%.
T E 30%.
U N 20%. .B(100,20%)
R T 10%.
E(%)0% . . . . . . . . . . . .
0 10 20 30 40 50 60 70 80 90 100 110
NO. OF BLOWS
STEP2: Join the coordinates A and B.
STEP3: draw the vertical line from 25 no. of blows to the line AB and mark it.
STEP4: Draw horizontal line from the marked point on line AB To the pt. on Y-axis, that same will give us the liquid limit of soil sample(ie. 65%).
(NOTE: ALL STEPS ARE TAKEN FROM EXPERIMENT OF DETERMINATION OF LIQUID LIMIT BY USING LIQUID LIMIT DEVICE)
(1)
Sagar Shah said:
1 decade ago
If we use flow index than the answer coming is 50. And plot shall be along log scale wouldn't rough idea from that be wrong?
Sharda charan said:
1 decade ago
Given;
n1=10; w1=70%.
n2=100; w2=20%.
Flow index (I)=(w1-w2)/log(n2/n1) = 50;.
wL = Ilog(n2/25)+w2;.
wL = 50.10%.
n1=10; w1=70%.
n2=100; w2=20%.
Flow index (I)=(w1-w2)/log(n2/n1) = 50;.
wL = Ilog(n2/25)+w2;.
wL = 50.10%.
V RAMESH said:
1 decade ago
Liquid Limit= W * (N/25)^0.121.
where,
W= water content at N blows.
N= no.of blows.
Liquid limit = 70*(10/25)^0121 = 89.55%.
Liquid Limit = 20*(100/25)^0.121 = 23.65%.
required liquid limit = 88-23 = 65%.
where,
W= water content at N blows.
N= no.of blows.
Liquid limit = 70*(10/25)^0121 = 89.55%.
Liquid Limit = 20*(100/25)^0.121 = 23.65%.
required liquid limit = 88-23 = 65%.
Pappu said:
1 decade ago
Liquid limit is define as water content at which the soil possesses an arbitrarily fixed small amount of shear strength.
Mudassir Abbas said:
1 decade ago
Just interpolate it on semi log graph paper. i.e No.of blows on logarithmic x-axis and m.c on y-axis and then find LL along 25 blows.
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