Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 45)
45.
A coarse-grained soil has a voids ratio 0.75, and specific gravity as 2.75. The critical gradient at which quick sand condition occurs, is
Discussion:
21 comments Page 1 of 3.
DIPANJAN BHADRA said:
4 years ago
Critical gradient (ID) = (G-1)/(1+e),
= (2.75-1)/(1+0.75),
= 1.
= (2.75-1)/(1+0.75),
= 1.
(3)
Ashok yadav said:
4 years ago
Ic = G-1/1+e,
= (2.75-1)/(1+0.75),
= 1.
= (2.75-1)/(1+0.75),
= 1.
(3)
Sahana said:
4 years ago
Compute the critical hydraulic gradient for a course gravel with k=6cm/sec gs=2.65 e=0.35.
(2)
Mayur said:
5 years ago
@ Khan,
i=(G-1)*((1-n).
i=(G-1)*((1-n).
Khan said:
6 years ago
What is the Relationship between porosity (n) and specific gravity (G) and critical hydraulic gradient (i)?
Vijaykumar said:
6 years ago
ic = (G-1)/(1+e).
ic = (2.75-1)/(1+0.75) = 1.
ic = (2.75-1)/(1+0.75) = 1.
(1)
Ashok tastode said:
6 years ago
Ic = G-1/1+e=2.67-1/1+0.67 = 1.67/1.67.
Hydraulic gradient i = hydraulic length/head.
1= h/1.5m.
H=1.5m.
Hydraulic gradient i = hydraulic length/head.
1= h/1.5m.
H=1.5m.
Dinker said:
6 years ago
Icr(for flowing water) = 3/5 = . 6.
And;
Icr (for soil) = (G-1)/(1+e) = (2.55-1)/(1+.55) = 1.
F.o.s = 1/.6 = 1.66.
And;
Icr (for soil) = (G-1)/(1+e) = (2.55-1)/(1+.55) = 1.
F.o.s = 1/.6 = 1.66.
Avshesh said:
7 years ago
Water is flowing in an upward direction through the structure of sand 5m thick under a total head difference of 3m. The sand has a specific gravity of 2.55 and voids ratio of 0.55. The factor of safety against quick condition would be?
Abhinandan kumar said:
7 years ago
ic=g-1/1+e then head loss =ic*thickness.
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