Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 45)
45.
A coarse-grained soil has a voids ratio 0.75, and specific gravity as 2.75. The critical gradient at which quick sand condition occurs, is
Discussion:
21 comments Page 1 of 3.
DIPANJAN BHADRA said:
4 years ago
Critical gradient (ID) = (G-1)/(1+e),
= (2.75-1)/(1+0.75),
= 1.
= (2.75-1)/(1+0.75),
= 1.
(3)
Ashok yadav said:
4 years ago
Ic = G-1/1+e,
= (2.75-1)/(1+0.75),
= 1.
= (2.75-1)/(1+0.75),
= 1.
(3)
Sahana said:
5 years ago
Compute the critical hydraulic gradient for a course gravel with k=6cm/sec gs=2.65 e=0.35.
(2)
Vijaykumar said:
6 years ago
ic = (G-1)/(1+e).
ic = (2.75-1)/(1+0.75) = 1.
ic = (2.75-1)/(1+0.75) = 1.
(1)
Avu said:
8 years ago
1.5 m @Rahul.
(1)
Ibraheem majeed said:
8 years ago
Head loss = hydraulic gradient * length or thickness.
Apply it you will get head loss as 1.5 @Rahul.
Apply it you will get head loss as 1.5 @Rahul.
Mayur said:
6 years ago
@ Khan,
i=(G-1)*((1-n).
i=(G-1)*((1-n).
Khan said:
6 years ago
What is the Relationship between porosity (n) and specific gravity (G) and critical hydraulic gradient (i)?
Ashok tastode said:
6 years ago
Ic = G-1/1+e=2.67-1/1+0.67 = 1.67/1.67.
Hydraulic gradient i = hydraulic length/head.
1= h/1.5m.
H=1.5m.
Hydraulic gradient i = hydraulic length/head.
1= h/1.5m.
H=1.5m.
Dinker said:
7 years ago
Icr(for flowing water) = 3/5 = . 6.
And;
Icr (for soil) = (G-1)/(1+e) = (2.55-1)/(1+.55) = 1.
F.o.s = 1/.6 = 1.66.
And;
Icr (for soil) = (G-1)/(1+e) = (2.55-1)/(1+.55) = 1.
F.o.s = 1/.6 = 1.66.
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