Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 45)
45.
A coarse-grained soil has a voids ratio 0.75, and specific gravity as 2.75. The critical gradient at which quick sand condition occurs, is
Discussion:
21 comments Page 2 of 3.
Ibraheem majeed said:
8 years ago
Head loss = hydraulic gradient * length or thickness.
Apply it you will get head loss as 1.5 @Rahul.
Apply it you will get head loss as 1.5 @Rahul.
Avu said:
8 years ago
1.5 m @Rahul.
(1)
Rahul said:
8 years ago
The hydraulic head that would produce a quick sand condition in a sand stratum of Thickness 1.5 m, specific gravity 2.67 and voids ratio 0.67 is equal to;
(a) 1.0 m
(b) 1.5 m
(c) 2.0 m
(d) 3.0 m
Please explain it with the answer.
(a) 1.0 m
(b) 1.5 m
(c) 2.0 m
(d) 3.0 m
Please explain it with the answer.
Abiral said:
9 years ago
We know that,
The critical hydraulic gradient = (G-1)/(1+e) = (2.75-1)/(1+0.75) = 1.
The critical hydraulic gradient = (G-1)/(1+e) = (2.75-1)/(1+0.75) = 1.
Pratyush said:
9 years ago
@Laxman.
Yes, you are right critical hydraulic gradient is always 1.
Yes, you are right critical hydraulic gradient is always 1.
JayRam said:
10 years ago
Critical hydraulic gradient (i) = G-1/1+e.
i = 2.5-1/1+0.75.
= 1.0.
i = 2.5-1/1+0.75.
= 1.0.
Bhakti said:
1 decade ago
Quick sand condition occurs in fine sand and silt.
Laxman said:
1 decade ago
Already they said critical gradient for critical hydraulic gradient is 1. no need of calculation.
PIYUSH SINGH said:
1 decade ago
Hydraulic Gradient (Id) = (G-1)/(1+e).
= (2.75-1) / (1+0.75).
= 1.
= (2.75-1) / (1+0.75).
= 1.
MANOJ KUMAR VERMA said:
1 decade ago
Critical hydraulic gradient = (G-1)/(1+e).
= (2.75-1)/(1+0.75).
= 1.00.
= (2.75-1)/(1+0.75).
= 1.00.
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