Civil Engineering - Irrigation - Discussion
Discussion Forum : Irrigation - Section 2 (Q.No. 10)
10.
If the irrigation efficiency is 80%, conveyance losses are 20% and the actual depth of watering is 16 cm, the depth of water required at the canal outlet, is
Discussion:
33 comments Page 2 of 4.
Khushi said:
6 years ago
Thanks @Sv Ranganadh.
Nareshsingh said:
6 years ago
X* (80/100)-x * (80/100 * 20/100) = 16.
So x = 25.
So x = 25.
Bhawesh said:
5 years ago
20/(0.8*0.8)=25.
80% Conveyance efficiency.
80% Irrigation Efficiency.
80% Conveyance efficiency.
80% Irrigation Efficiency.
Bhumika Varshney said:
5 years ago
Not getting, please anyone explain.
Samim said:
5 years ago
16/(0.8 *0.8) = 25.
80% = 0.8,
100 - 20 % = 0.8.
80% = 0.8,
100 - 20 % = 0.8.
Akash vardhan said:
7 years ago
Thanks all of you for explaining the answer.
Shahid said:
4 years ago
0.8x - (0.8x * 0.2) = 16.
Then, x = 25cm.
Then, x = 25cm.
Farhan said:
3 weeks ago
ir efi = 80% = 0.8.
con efi = 100 - 20 = 0.8,
Overall E = 0.8 * 0.8 = 0.64,
D at outlet = 16/0.64 = 25cm.
con efi = 100 - 20 = 0.8,
Overall E = 0.8 * 0.8 = 0.64,
D at outlet = 16/0.64 = 25cm.
Mayur said:
7 years ago
Not understood. Please explain me clearly.
GSHAH said:
1 decade ago
Taking 25 as a flow, loss = 25*.20 = 5.
Remain = 20 efficiency = 80%.
So .20*.80 = 16.
Answer is 25 c.m.
Remain = 20 efficiency = 80%.
So .20*.80 = 16.
Answer is 25 c.m.
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