Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 3 (Q.No. 1)
1.
For exerting a pressure of 4.8 kg/cm2, the depth of oil (specific gravity 0.8), should be
Discussion:
24 comments Page 3 of 3.
Honey said:
9 years ago
Here, it is converted it in newton by multiplying 10.
Another way to do it is, 1st convert 4.8kg/cm2 into kg/m2 by multiplying it with 10000.
Ten again multiply by 10 to get in N/m2, then find out the specific weight.
=> 8 * 1000 * 10 now divide 480000/8000.
You will get 60 as an answer.
Another way to do it is, 1st convert 4.8kg/cm2 into kg/m2 by multiplying it with 10000.
Ten again multiply by 10 to get in N/m2, then find out the specific weight.
=> 8 * 1000 * 10 now divide 480000/8000.
You will get 60 as an answer.
Shubham said:
9 years ago
@Brijendra.
Tell me how you converted 4.8 to 48?
Tell me how you converted 4.8 to 48?
Binktesh kumar said:
9 years ago
Hello, @Brijendra.
How you take pressure 4.8 to 48?
How you take pressure 4.8 to 48?
Rashid said:
9 years ago
Hi, @Brijendra.
How you take 4.8 as 48?
How you take 4.8 as 48?
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