Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 3 (Q.No. 1)
1.
For exerting a pressure of 4.8 kg/cm2, the depth of oil (specific gravity 0.8), should be
Discussion:
24 comments Page 2 of 3.
MaNiSh said:
8 years ago
@ALL.
P=4.8kg/cm^2---> (1)
Now we know that 1kg=10N, put in---> (1)
P=48N/cm^2.
W=.8.
Now calculate hight by formula-P=w.h.
And get answer 60 cm.
P=4.8kg/cm^2---> (1)
Now we know that 1kg=10N, put in---> (1)
P=48N/cm^2.
W=.8.
Now calculate hight by formula-P=w.h.
And get answer 60 cm.
Sadulla Ahmed said:
7 years ago
Yes, it's 60m. I agree.
Brijendra said:
1 decade ago
P=WH, H=P/W, H=48/.8=60.
Sanjay said:
8 years ago
Yes, they all are right, the answer must be in a meter.
BIBEK said:
8 years ago
Answer 60 m is correct. I agree.
BASTARD said:
8 years ago
PRESSURE=(UNIT WT.)*(HEIGHT).
4.8 = (0.8)*(1000/100^3)*(H),
H = 6000 cm.
H = 60 m.
4.8 = (0.8)*(1000/100^3)*(H),
H = 6000 cm.
H = 60 m.
Abhishek Anand said:
9 years ago
Answer must be 60m. I agree.
Rind said:
9 years ago
H = p/w.
= 48/.8,
= 60.
= 48/.8,
= 60.
Sasi said:
9 years ago
Pressure = W * H.
4.8 * 10^3 = sp. grvty * dnsty * H.
4800 = 0.8 * 1* H.
H = 6000cm = 60m.
4.8 * 10^3 = sp. grvty * dnsty * H.
4800 = 0.8 * 1* H.
H = 6000cm = 60m.
Disha said:
9 years ago
Explain briefly!
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