Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 5 (Q.No. 30)
30.
Interior thickness of concrete road slab for design wheel load 6300 kg and permissible flexural stress 21 kg/cm2, is
17.0 cm
25.5 cm
34.0 cm
42.5 cm
50.0 cm
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
17 comments Page 1 of 2.

Dev said:   4 years ago
depth of concrete = d = √(3w/stress),
d= √(3*6300/21)=30,

Now,
Thickness of Concrete= 0.85*d,
t=0.85*30,
t=25.5cm.
(6)

Hima said:   4 years ago
The depth and thickness of concrete pavement is the same.

As cross-section of concrete pavement is Double trapezoidal. So thickness or depth at the interior of concrete pavement is equal to 0. 85 thickness or depth at sides of concrete pavement.

Depth/thickness of concrete pavement is given by (3W/flexural stress). Where W = wheel load.

Anirban Roy said:   5 years ago
Using Goldbeck equation:

t = (3W÷stress)^0.5.
t interior = 0.85t.

Burhan said:   5 years ago
Wheel load 3600.

Stress 21
√3 * 3600/21=√300=30
Now
.85* d= .85 * 30 = 25.5cm.

Prashant said:   6 years ago
What is the difference between the depth of concrete and thickness of concrete @Quasim.

Akhil said:   6 years ago
Thank you all for explaining the answer.

Ammy said:   7 years ago
Thank you @Qasim.
(1)

Kohli said:   7 years ago
Thanks @Qasim.

Qasim said:   8 years ago
depth of concrete=d= sqrt(3w/stress),
d=sqrt(3*6300/21)=30,

Now,
Thickness of Concrete= 0.85*d,
t=0.85*30,
t=25.5cm.
(2)

Anbu star lion said:   8 years ago
Thanks @Praveen and @Sam.


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