Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 5 (Q.No. 30)
30.
Interior thickness of concrete road slab for design wheel load 6300 kg and permissible flexural stress 21 kg/cm2, is
Discussion:
17 comments Page 2 of 2.
Roy said:
8 years ago
Thanks @Praveen and @Sam.
Praveen said:
9 years ago
Thickness will be 0.85 * 30 = 25.5.
SAM said:
9 years ago
d = (3W/stress)^0.5,
= (3 * 6300/21)^0.5,
= 30.
= (3 * 6300/21)^0.5,
= 30.
Jehangir khan said:
9 years ago
Please provide the explanation.
Arya said:
9 years ago
Stress = load/area,
Thickness at interior is 0.85 d.
Thickness at interior is 0.85 d.
Jogendra said:
9 years ago
Provide the explanation of the solution.
Arnab Chanda said:
9 years ago
Please give me the explanation.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers