Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 5 (Q.No. 30)

Highway Engineering

30.

Interior thickness of concrete road slab for design wheel load 6300 kg and permissible flexural stress 21 kg/cm², is

17.0 cm

25.5 cm

34.0 cm

42.5 cm

50.0 cm

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

17 comments Page 1 of 2.

Arnab Chanda said: 9 years ago

Please give me the explanation.

Jogendra said: 9 years ago

Provide the explanation of the solution.

Arya said: 9 years ago

Stress = load/area,

Thickness at interior is 0.85 d.

Jehangir khan said: 9 years ago

Please provide the explanation.

SAM said: 9 years ago

d = (3W/stress)^0.5,
= (3 * 6300/21)^0.5,
= 30.

Praveen said: 9 years ago

Thickness will be 0.85 * 30 = 25.5.

Roy said: 8 years ago

Thanks @Praveen and @Sam.

Anbu star lion said: 8 years ago

Thanks @Praveen and @Sam.

Qasim said: 8 years ago

depth of concrete=d= sqrt(3w/stress),
d=sqrt(3*6300/21)=30,

Now,
Thickness of Concrete= 0.85*d,
t=0.85*30,
t=25.5cm.

(2)

Kohli said: 7 years ago

Thanks @Qasim.

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers