Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 5 (Q.No. 30)
30.
Interior thickness of concrete road slab for design wheel load 6300 kg and permissible flexural stress 21 kg/cm2, is
17.0 cm
25.5 cm
34.0 cm
42.5 cm
50.0 cm
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
17 comments Page 1 of 2.

Hima said:   4 years ago
The depth and thickness of concrete pavement is the same.

As cross-section of concrete pavement is Double trapezoidal. So thickness or depth at the interior of concrete pavement is equal to 0. 85 thickness or depth at sides of concrete pavement.

Depth/thickness of concrete pavement is given by (3W/flexural stress). Where W = wheel load.

Dev said:   4 years ago
depth of concrete = d = √(3w/stress),
d= √(3*6300/21)=30,

Now,
Thickness of Concrete= 0.85*d,
t=0.85*30,
t=25.5cm.
(6)

Qasim said:   8 years ago
depth of concrete=d= sqrt(3w/stress),
d=sqrt(3*6300/21)=30,

Now,
Thickness of Concrete= 0.85*d,
t=0.85*30,
t=25.5cm.
(2)

Burhan said:   5 years ago
Wheel load 3600.

Stress 21
√3 * 3600/21=√300=30
Now
.85* d= .85 * 30 = 25.5cm.

Prashant said:   6 years ago
What is the difference between the depth of concrete and thickness of concrete @Quasim.

Anirban Roy said:   5 years ago
Using Goldbeck equation:

t = (3W÷stress)^0.5.
t interior = 0.85t.

Arya said:   9 years ago
Stress = load/area,

Thickness at interior is 0.85 d.

SAM said:   9 years ago
d = (3W/stress)^0.5,
= (3 * 6300/21)^0.5,
= 30.

Akhil said:   6 years ago
Thank you all for explaining the answer.

Jogendra said:   9 years ago
Provide the explanation of the solution.


Post your comments here:

Your comments will be displayed after verification.