Civil Engineering - Construction Management - Discussion
Discussion Forum : Construction Management - Section 2 (Q.No. 32)
32.
The three time estimates for the activities of the network shown in the given figure are shown above their arrows. The earliest expected time for the event 4, is
Discussion:
8 comments Page 1 of 1.
Zahid said:
1 decade ago
Using PERT formula for each activity. Add the value obtained to get 19.
Activity 1-2 => (3+(4*4)+5)/6 = 4.
2-3 =>(5+(7*4)+9)/6 = 7.
3-4 => (6+(4*4)+10)/6 = 8.
4+7+8 = 19.
Activity 1-2 => (3+(4*4)+5)/6 = 4.
2-3 =>(5+(7*4)+9)/6 = 7.
3-4 => (6+(4*4)+10)/6 = 8.
4+7+8 = 19.
(5)
Dinesh gupta said:
3 years ago
1-2=>(3+(4*4)+5)/6 = 24/6 = 4.
2-3=>(5+(7*4)+9)/6 = 42/6 = 7.
3-4=>(6+(8*4)+10)/6 = 48/6 = 8.
2-3=>(5+(7*4)+9)/6 = 42/6 = 7.
3-4=>(6+(8*4)+10)/6 = 48/6 = 8.
(4)
Uttu said:
7 years ago
@Subha.
Activity 4 cannot be started without activity 1 2 & 3.
So, 19 is correct.
Activity 4 cannot be started without activity 1 2 & 3.
So, 19 is correct.
(3)
Sabina said:
5 years ago
@Zahid.
Activity 3-4 calculation is wrong by;
Expected time= 6 + 4 * 8 + 10/6 = 8.
Activity 3-4 calculation is wrong by;
Expected time= 6 + 4 * 8 + 10/6 = 8.
Subha Annadurai said:
7 years ago
According to me, 3-4=>(6+(8*4)+10)/6 = 8.
Lalitha said:
7 years ago
Nice explanation. Thank you @Zahid.
Dev Kumavat said:
7 years ago
Thank you @Zahid.
Bhai said:
9 years ago
Nice @Zahid.
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