Civil Engineering - Concrete Technology - Discussion

22. 

If the effective plan area of a warehouse is 54 sq. m, and maximum height of piles permitted is 270 cm, the number of cement bags to be stored, is

[A]. 2000 bags
[B]. 2200 bags
[C]. 2400 bags
[D]. 2700 bags
[E]. 3000 bags

Answer: Option D

Explanation:

No answer description available for this question.

Kenmen said: (Jul 16, 2015)  
We know, surface area and height of pile required for storing of 1 bag of cement are 0.3 sq. m. and 0.18 m respectively.

Therefore, maximum nos of bags can be stored into the given stored house = (5.4 x 2.7)/(0.3 x 0.18) = 2700 bags.

Sivareddy said: (Mar 13, 2016)  
How did you change 54 sq meters in 5.4?

Please explain about it.

Darshan H A said: (Jul 5, 2016)  
Surface area and height of pile required for storing of 1 bag of cement is 0.3 sq M and 0.18 m.

Therefore maximum number of bags can be stored into the given house = (54 x 2.7) / (0.3 x 0.18) = 2700 bags.

Vivek Bhardwaj said: (Feb 28, 2017)  
One bag of cement occupy 0.034cum vol.

Why you take 0.054?

Anurag Garg said: (Dec 26, 2017)  
But as per rules, it is necessary to keep min 30 cm distance between the wall and first column of cement to avoid moisture.

Chris said: (Feb 3, 2018)  
Effective plan area is given. Already 30cm excluded.

Ravneet said: (Sep 30, 2018)  
The total volume of room 54 * 2.7.
The volume of 1 cement bag .0347.
The Number of cement bags = 54 * 2.7/.0347 = 4200.

Jas said: (Oct 13, 2018)  
It's the volume of cement bag not of cement;

Height of bag - 0.18m (or) 18 cm.
And area - 0.3sqm (or) 3000 sq cm.
So the volume of bag = 0.18 * 0.3 = 0.054 cum,
Volume of room - 54 * 2.7= 145.8 cum.

No of bags= volume of room (warehouse)/volume of one cement bag.
= 54 * 2.7/(0.18 * 0.3),
=145.8/0.054,
= 2700.

Deepu Maurya said: (Oct 21, 2018)  
54 * 2.7 ÷ (.054) = 2700.

Sami said: (Feb 14, 2019)  
How to find the height and area bag?

Sikindra Yadav said: (Feb 16, 2019)  
Yeah, you are right, agree @Darshan H A.

Rahul Swarnkar said: (Sep 7, 2019)  
54*2.7/.18*.3 = 2700 bags.

Yash said: (Nov 19, 2019)  
When you take 1 bag of cement and plan on group its cover 3000 sq cm area.
And bag height is 18 cm.
That by they use .3 Sqm and .18m here For a bag.

Beewaek Mandal said: (Jan 8, 2020)  
Simply,

No. Of bags = Effective area* Max.ht of piles/ Area coverd by one bag cement is 0.3 sq.m & ht= 0.18.

No= 54*2.7/0.3*0.18 = 2700 bags you must get.

Er. Anshu Kumar said: (Jun 19, 2020)  
Here,

In first case: (standard):

Area required for 1 bag of cement = 0.3 sq.m,
Height of pile required for 1 bag = 0.18 m,
Volume of 1 bag = 0.3 * 0.18,
= 0.054 cubic metre.

In second case:(Given):
Plan area of warehouse = 54 sq.m,
Max.height of piles = 270 cm =2.7 m,
Volume of warehouse = 54*2.7.
= 145.8 cubic metre.

We know that;
No.of bags = volume of warehouse/volume of 1 bag of cement.
= 145.8/0.054.
= 2700 bags.(Answer).

Chandan Nandi said: (Aug 6, 2020)  
2.7 How come?

Please explain.

Longti said: (Nov 27, 2020)  
270cm = 2.7m.

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