### Discussion :: Concrete Technology - Section 4 (Q.No.22)

Kenmen said: (Jul 16, 2015) | |

We know, surface area and height of pile required for storing of 1 bag of cement are 0.3 sq. m. and 0.18 m respectively. Therefore, maximum nos of bags can be stored into the given stored house = (5.4 x 2.7)/(0.3 x 0.18) = 2700 bags. |

Sivareddy said: (Mar 13, 2016) | |

How did you change 54 sq meters in 5.4? Please explain about it. |

Darshan H A said: (Jul 5, 2016) | |

Surface area and height of pile required for storing of 1 bag of cement is 0.3 sq M and 0.18 m. Therefore maximum number of bags can be stored into the given house = (54 x 2.7) / (0.3 x 0.18) = 2700 bags. |

Vivek Bhardwaj said: (Feb 28, 2017) | |

One bag of cement occupy 0.034cum vol. Why you take 0.054? |

Anurag Garg said: (Dec 26, 2017) | |

But as per rules, it is necessary to keep min 30 cm distance between the wall and first column of cement to avoid moisture. |

Chris said: (Feb 3, 2018) | |

Effective plan area is given. Already 30cm excluded. |

Ravneet said: (Sep 30, 2018) | |

The total volume of room 54 * 2.7. The volume of 1 cement bag .0347. The Number of cement bags = 54 * 2.7/.0347 = 4200. |

Jas said: (Oct 13, 2018) | |

It's the volume of cement bag not of cement; Height of bag - 0.18m (or) 18 cm. And area - 0.3sqm (or) 3000 sq cm. So the volume of bag = 0.18 * 0.3 = 0.054 cum, Volume of room - 54 * 2.7= 145.8 cum. No of bags= volume of room (warehouse)/volume of one cement bag. = 54 * 2.7/(0.18 * 0.3), =145.8/0.054, = 2700. |

Deepu Maurya said: (Oct 21, 2018) | |

54 * 2.7 ÷ (.054) = 2700. |

Sami said: (Feb 14, 2019) | |

How to find the height and area bag? |

Sikindra Yadav said: (Feb 16, 2019) | |

Yeah, you are right, agree @Darshan H A. |

Rahul Swarnkar said: (Sep 7, 2019) | |

54*2.7/.18*.3 = 2700 bags. |

Yash said: (Nov 19, 2019) | |

When you take 1 bag of cement and plan on group its cover 3000 sq cm area. And bag height is 18 cm. That by they use .3 Sqm and .18m here For a bag. |

Beewaek Mandal said: (Jan 8, 2020) | |

Simply, No. Of bags = Effective area* Max.ht of piles/ Area coverd by one bag cement is 0.3 sq.m & ht= 0.18. No= 54*2.7/0.3*0.18 = 2700 bags you must get. |

Er. Anshu Kumar said: (Jun 19, 2020) | |

Here, In first case: (standard): Area required for 1 bag of cement = 0.3 sq.m, Height of pile required for 1 bag = 0.18 m, Volume of 1 bag = 0.3 * 0.18, = 0.054 cubic metre. In second case:(Given): Plan area of warehouse = 54 sq.m, Max.height of piles = 270 cm =2.7 m, Volume of warehouse = 54*2.7. = 145.8 cubic metre. We know that; No.of bags = volume of warehouse/volume of 1 bag of cement. = 145.8/0.054. = 2700 bags.(Answer). |

Chandan Nandi said: (Aug 6, 2020) | |

2.7 How come? Please explain. |

Longti said: (Nov 27, 2020) | |

270cm = 2.7m. |

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