Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 4 (Q.No. 22)
22.
If the effective plan area of a warehouse is 54 sq. m, and maximum height of piles permitted is 270 cm, the number of cement bags to be stored, is
2000 bags
2200 bags
2400 bags
2700 bags
3000 bags
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
21 comments Page 2 of 3.

Sikindra yadav said:   7 years ago
Yeah, you are right, agree @Darshan H A.
(1)

Sami said:   7 years ago
How to find the height and area bag?

Deepu Maurya said:   7 years ago
54 * 2.7 ÷ (.054) = 2700.

Jas said:   7 years ago
It's the volume of cement bag not of cement;

Height of bag - 0.18m (or) 18 cm.
And area - 0.3sqm (or) 3000 sq cm.
So the volume of bag = 0.18 * 0.3 = 0.054 cum,
Volume of room - 54 * 2.7= 145.8 cum.

No of bags= volume of room (warehouse)/volume of one cement bag.
= 54 * 2.7/(0.18 * 0.3),
=145.8/0.054,
= 2700.

Ravneet said:   7 years ago
The total volume of room 54 * 2.7.
The volume of 1 cement bag .0347.
The Number of cement bags = 54 * 2.7/.0347 = 4200.

Chris said:   8 years ago
Effective plan area is given. Already 30cm excluded.

ANURAG GARG said:   8 years ago
But as per rules, it is necessary to keep min 30 cm distance between the wall and first column of cement to avoid moisture.

Vivek bhardwaj said:   9 years ago
One bag of cement occupy 0.034cum vol.

Why you take 0.054?

Darshan h a said:   9 years ago
Surface area and height of pile required for storing of 1 bag of cement is 0.3 sq M and 0.18 m.

Therefore maximum number of bags can be stored into the given house = (54 x 2.7) / (0.3 x 0.18) = 2700 bags.

Sivareddy said:   9 years ago
How did you change 54 sq meters in 5.4?

Please explain about it.


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