Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 4 (Q.No. 40)
40.
For preparing ordinary concrete, the quantity of water used, is
Discussion:
10 comments Page 1 of 1.
MD Shekhar said:
8 years ago
Wt.of water = 5% by weight of aggregates plus 30% of weight of cement.
For M15(1:2:4):
Water = 5%*6(50kg)+30%*(50kg) = 30kg.
For M15(1:2:4):
Water = 5%*6(50kg)+30%*(50kg) = 30kg.
(1)
RaHul Verma said:
6 years ago
38% water by weight of cement is required for complete hydration of cement and to fill gel pores so the correct option is C.
(1)
Agha Bilal said:
7 months ago
Option C is Correct.
5% by weight of aggregates plus 30% by weight of cement.
5% by weight of aggregates plus 30% by weight of cement.
(1)
S daterao said:
9 years ago
Please anyone explain it.
Ashley Hope said:
9 years ago
How to know? Please Explain.
Saudagar said:
8 years ago
@Md Shekhar.
On what basis you take 5%*6(50) can you explain me or anyone explains me.
On what basis you take 5%*6(50) can you explain me or anyone explains me.
Sabin Shrestha said:
7 years ago
@Saudagar.
6= 2+4 as aggregates represents "fine(2) +Course(4)".
6= 2+4 as aggregates represents "fine(2) +Course(4)".
Amrit chhetri said:
6 years ago
What method has been used here?
Bibek said:
4 years ago
1:6(agg:cement) =5% * 30% (not standard)
Yousuf Nazar said:
2 years ago
The given answer is wrong.
according to my opinion, In the case of normal concretes, on average 23% of water by weight of cement is required for chemical reaction with Portland cement compounds.
About 15% water by weight of cement is required to fill the pores created during hydration i.e CSH gel pores.
according to my opinion, In the case of normal concretes, on average 23% of water by weight of cement is required for chemical reaction with Portland cement compounds.
About 15% water by weight of cement is required to fill the pores created during hydration i.e CSH gel pores.
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