# Civil Engineering - Concrete Technology - Discussion

### Discussion :: Concrete Technology - Section 4 (Q.No.40)

40.

For preparing ordinary concrete, the quantity of water used, is

 [A]. 5% by weight of aggregates plus 20% of weight of cement [B]. 10% by weight of aggregates plus 10% of weight of cement [C]. 5% by weight of aggregates plus 30% of weight of cement [D]. 30% by weight of aggregates plus 10% of weight of cement [E]. none of these.

Explanation:

No answer description available for this question.

 S Daterao said: (Nov 7, 2016) Please anyone explain it.

 Ashley Hope said: (Nov 25, 2016) How to know? Please Explain.

 Md Shekhar said: (Nov 12, 2017) Wt.of water = 5% by weight of aggregates plus 30% of weight of cement. For M15(1:2:4): Water = 5%*6(50kg)+30%*(50kg) = 30kg.

 Saudagar said: (Nov 20, 2017) @Md Shekhar. On what basis you take 5%*6(50) can you explain me or anyone explains me.

 Sabin Shrestha said: (Nov 19, 2018) @Saudagar. 6= 2+4 as aggregates represents "fine(2) +Course(4)".

 Rahul Verma said: (Jun 17, 2019) 38% water by weight of cement is required for complete hydration of cement and to fill gel pores so the correct option is C.

 Amrit Chhetri said: (Nov 29, 2019) What method has been used here?