Civil Engineering - Concrete Technology - Discussion

40. 

For preparing ordinary concrete, the quantity of water used, is

[A]. 5% by weight of aggregates plus 20% of weight of cement
[B]. 10% by weight of aggregates plus 10% of weight of cement
[C]. 5% by weight of aggregates plus 30% of weight of cement
[D]. 30% by weight of aggregates plus 10% of weight of cement
[E]. none of these.

Answer: Option C

Explanation:

No answer description available for this question.

S Daterao said: (Nov 7, 2016)  
Please anyone explain it.

Ashley Hope said: (Nov 25, 2016)  
How to know? Please Explain.

Md Shekhar said: (Nov 12, 2017)  
Wt.of water = 5% by weight of aggregates plus 30% of weight of cement.

For M15(1:2:4):
Water = 5%*6(50kg)+30%*(50kg) = 30kg.

Saudagar said: (Nov 20, 2017)  
@Md Shekhar.

On what basis you take 5%*6(50) can you explain me or anyone explains me.

Sabin Shrestha said: (Nov 19, 2018)  
@Saudagar.

6= 2+4 as aggregates represents "fine(2) +Course(4)".

Rahul Verma said: (Jun 17, 2019)  
38% water by weight of cement is required for complete hydration of cement and to fill gel pores so the correct option is C.

Amrit Chhetri said: (Nov 29, 2019)  
What method has been used here?

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