Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 35)
35.
The percentage of the aggregate of F.M. 2.6 to be combined with coarse aggregate of F.M. 6.8 for obtaining the aggregates of F.M. 5.4, is
Discussion:
23 comments Page 2 of 3.
Chintu said:
6 years ago
Let the proportion of FA is =p.
Then, proportion of CA will be =1-p , as sum of proportion is always 1.
So, 2.6p+6.8(1-p)=5.4 , by solving it we get, p=1/3=0.33, i.e in percentage it is 33.33% .
But in option appropriate answer will be 30%.
Then, proportion of CA will be =1-p , as sum of proportion is always 1.
So, 2.6p+6.8(1-p)=5.4 , by solving it we get, p=1/3=0.33, i.e in percentage it is 33.33% .
But in option appropriate answer will be 30%.
Chintu said:
6 years ago
Agree @Naveen Kallan.
The Answer is 33.33%.
The Answer is 33.33%.
Gopal said:
6 years ago
Yes, you are right, Thanks @Naveen Kallan.
PRATIK BASAK said:
1 decade ago
Formula is (X-Z)/(Z-Y)*100.
Here X - 6.8, Y - 2.6, Z - 5.4.
Here X - 6.8, Y - 2.6, Z - 5.4.
Vivek yadav said:
7 years ago
50% is correct.
Vikrantsinghchauhan said:
7 years ago
I am not understanding. Please explain the correct answer of this question.
Rabindra said:
7 years ago
Nice @Pratik.
Naveen Kallan said:
8 years ago
If it is the ratio of fine to coarse then only ans is 50%.
If it is percentage then ans is X-Z/X-Y = 33.33%.
If it is percentage then ans is X-Z/X-Y = 33.33%.
Pritam said:
8 years ago
When it is given "to be combined", the solution is given as (6.8-5.4)/(6.8-2.6).
Vishvas said:
8 years ago
X = % coarse aggregates.
Y = % fine aggregates.
Z = % combined aggregates.
Y = % fine aggregates.
Z = % combined aggregates.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers