Discussion :: Concrete Technology - Section 2 (Q.No.35)
| Pratik Basak said: (Jan 3, 2015) | |
| Formula is (X-Z)/(Z-Y)*100. Here X - 6.8, Y - 2.6, Z - 5.4. |
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| Agar said: (Dec 8, 2015) | |
| FM mean? | |
| Rajesh said: (Jan 26, 2016) | |
| Fineness Modulus-FM. | |
| Nabin Chandra Das From Gimt said: (Jan 27, 2016) | |
| {(6.8-5.4)/(5.4-2.6)}*100 = 50% x = 6.8, y = 2.6, z = 5.4. C is correct answer. |
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| Amrit Raj said: (Mar 18, 2017) | |
| How can we determine the value of X, Y and Z? | |
| Vishvas said: (Jun 3, 2017) | |
| X = % coarse aggregates. Y = % fine aggregates. Z = % combined aggregates. |
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| Pritam said: (Sep 28, 2017) | |
| When it is given "to be combined", the solution is given as (6.8-5.4)/(6.8-2.6). | |
| Naveen Kallan said: (Oct 9, 2017) | |
| If it is the ratio of fine to coarse then only ans is 50%. If it is percentage then ans is X-Z/X-Y = 33.33%. |
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| Rabindra said: (Apr 18, 2018) | |
| Nice @Pratik. | |
| Vikrantsinghchauhan said: (Sep 24, 2018) | |
| I am not understanding. Please explain the correct answer of this question. | |
| Vivek Yadav said: (Oct 8, 2018) | |
| 50% is correct. | |
| Mrityunjoy Mete said: (Nov 16, 2018) | |
| the fine aggregate of finesse modulus 2.6 is mix with a coarse aggregate of finesse modulus 6.8 for obtaining the aggregate of finesse modulus 5.4 then find our the percentage of coarse aggregate in the mix? Can anybody answer this? |
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| Gopal said: (Jun 11, 2019) | |
| Yes, you are right, Thanks @Naveen Kallan. | |
| Chintu said: (Jul 21, 2019) | |
| Agree @Naveen Kallan. The Answer is 33.33%. |
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| Chintu said: (Jul 21, 2019) | |
| Let the proportion of FA is =p. Then, proportion of CA will be =1-p , as sum of proportion is always 1. So, 2.6p+6.8(1-p)=5.4 , by solving it we get, p=1/3=0.33, i.e in percentage it is 33.33% . But in option appropriate answer will be 30%. |
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| Anoms said: (Aug 15, 2019) | |
| (coarse -Combine)/(Combine-Fine) * 100. So, (6.8-5.4)/(5.4-2.6)*100 = 50%. |
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