Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 2 (Q.No. 35)
35.
The percentage of the aggregate of F.M. 2.6 to be combined with coarse aggregate of F.M. 6.8 for obtaining the aggregates of F.M. 5.4, is
30%
40%
50%
60%.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
23 comments Page 1 of 3.

SHASHANK said:   2 years ago
X=P2-P/P-P1*100.

P2=6.8.
P1= 2.8.
P=5.4.

X= 6.8-5.4/5.4 - 2.8 * 100.
= 50%.
(3)

Pankaj Nagar said:   3 years ago
Here, The percentage of the aggregate of F.M. 2.6 to be combined.

i.e If the total amount of F.M 2.6 is 100% now then how much % of Aggregate will be required to obtain an F.M 5.4 with 100% amount of F. M. 6.8 aggregates.

Khaled Mahmoud said:   3 years ago
Can anyone give me feedback about the previous percent 50%, Is this percent is relative to the total mix volume or related to the total volume of aggregates (coarse and fine)? Please explain me.

Dawood khan said:   3 years ago
5O is the correct answer.

FM= x-z/z-y x100.
X= coarse agg which is 6.8.
Y = fine agg which is 2.6.
Z= combined or obtained agg which is= 5.4.
Now put the values in the above formula,
= 6.8-5.4/5.4-2.6x100.
=1.4/2.8x100,
= 0.5x100,
= 50.
(4)

Rahul said:   4 years ago
@Mrityunjoy mete.

First, find the percentage of fine aggregate by FMc-FMcom/FMcm-FMf.

Then the percentage of coarse aggregate will be 100- the percentage of fine aggregate.

Khongthaw said:   4 years ago
Let Fine aggregates be P1.
Course aggregates be P2.
Combined aggregates be P.
Given: P1=2.6, P2=6.8 and P=5.4.
Fineness modulus = (P2 - P/P-P1) * 100.
= 50%.
(1)

Anand Ratan said:   5 years ago
X = course aggregates.
Y = fine aggregates.
Z = combined aggregates.

Formula ,
Fine modules ( % )= ( x - z / z - y ) x 100
=( 6.8 - 5.4 / 5.2 - 2.6 ) x 100
= 50%
Correct answer is C .

Anoms said:   5 years ago
(coarse -Combine)/(Combine-Fine) * 100.
So, (6.8-5.4)/(5.4-2.6)*100 = 50%.

Chintu said:   5 years ago
Let the proportion of FA is =p.

Then, proportion of CA will be =1-p , as sum of proportion is always 1.
So, 2.6p+6.8(1-p)=5.4 , by solving it we get, p=1/3=0.33, i.e in percentage it is 33.33% .
But in option appropriate answer will be 30%.

Chintu said:   5 years ago
Agree @Naveen Kallan.

The Answer is 33.33%.


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