Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 35)
35.
The percentage of the aggregate of F.M. 2.6 to be combined with coarse aggregate of F.M. 6.8 for obtaining the aggregates of F.M. 5.4, is
Discussion:
23 comments Page 2 of 3.
Gopal said:
6 years ago
Yes, you are right, Thanks @Naveen Kallan.
Mrityunjoy Mete said:
7 years ago
the fine aggregate of finesse modulus 2.6 is mix with a coarse aggregate of finesse modulus 6.8 for obtaining the aggregate of finesse modulus 5.4 then find our the percentage of coarse aggregate in the mix?
Can anybody answer this?
Can anybody answer this?
Vivek yadav said:
7 years ago
50% is correct.
Vikrantsinghchauhan said:
7 years ago
I am not understanding. Please explain the correct answer of this question.
Rabindra said:
7 years ago
Nice @Pratik.
Naveen Kallan said:
8 years ago
If it is the ratio of fine to coarse then only ans is 50%.
If it is percentage then ans is X-Z/X-Y = 33.33%.
If it is percentage then ans is X-Z/X-Y = 33.33%.
Pritam said:
8 years ago
When it is given "to be combined", the solution is given as (6.8-5.4)/(6.8-2.6).
Vishvas said:
8 years ago
X = % coarse aggregates.
Y = % fine aggregates.
Z = % combined aggregates.
Y = % fine aggregates.
Z = % combined aggregates.
Amrit Raj said:
8 years ago
How can we determine the value of X, Y and Z?
(1)
NABIN CHANDRA DAS FROM GIMT said:
10 years ago
{(6.8-5.4)/(5.4-2.6)}*100 = 50%
x = 6.8, y = 2.6, z = 5.4.
C is correct answer.
x = 6.8, y = 2.6, z = 5.4.
C is correct answer.
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