Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 35)
35.
The percentage of the aggregate of F.M. 2.6 to be combined with coarse aggregate of F.M. 6.8 for obtaining the aggregates of F.M. 5.4, is
Discussion:
23 comments Page 1 of 3.
PRATIK BASAK said:
1 decade ago
Formula is (X-Z)/(Z-Y)*100.
Here X - 6.8, Y - 2.6, Z - 5.4.
Here X - 6.8, Y - 2.6, Z - 5.4.
Agar said:
10 years ago
FM mean?
Rajesh said:
10 years ago
Fineness Modulus-FM.
NABIN CHANDRA DAS FROM GIMT said:
10 years ago
{(6.8-5.4)/(5.4-2.6)}*100 = 50%
x = 6.8, y = 2.6, z = 5.4.
C is correct answer.
x = 6.8, y = 2.6, z = 5.4.
C is correct answer.
Amrit Raj said:
8 years ago
How can we determine the value of X, Y and Z?
(1)
Vishvas said:
8 years ago
X = % coarse aggregates.
Y = % fine aggregates.
Z = % combined aggregates.
Y = % fine aggregates.
Z = % combined aggregates.
Pritam said:
8 years ago
When it is given "to be combined", the solution is given as (6.8-5.4)/(6.8-2.6).
Naveen Kallan said:
8 years ago
If it is the ratio of fine to coarse then only ans is 50%.
If it is percentage then ans is X-Z/X-Y = 33.33%.
If it is percentage then ans is X-Z/X-Y = 33.33%.
Rabindra said:
7 years ago
Nice @Pratik.
Vikrantsinghchauhan said:
7 years ago
I am not understanding. Please explain the correct answer of this question.
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