Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 35)
35.
The percentage of the aggregate of F.M. 2.6 to be combined with coarse aggregate of F.M. 6.8 for obtaining the aggregates of F.M. 5.4, is
Discussion:
23 comments Page 2 of 3.
Vivek yadav said:
7 years ago
50% is correct.
Mrityunjoy Mete said:
7 years ago
the fine aggregate of finesse modulus 2.6 is mix with a coarse aggregate of finesse modulus 6.8 for obtaining the aggregate of finesse modulus 5.4 then find our the percentage of coarse aggregate in the mix?
Can anybody answer this?
Can anybody answer this?
Gopal said:
6 years ago
Yes, you are right, Thanks @Naveen Kallan.
Chintu said:
6 years ago
Agree @Naveen Kallan.
The Answer is 33.33%.
The Answer is 33.33%.
Chintu said:
6 years ago
Let the proportion of FA is =p.
Then, proportion of CA will be =1-p , as sum of proportion is always 1.
So, 2.6p+6.8(1-p)=5.4 , by solving it we get, p=1/3=0.33, i.e in percentage it is 33.33% .
But in option appropriate answer will be 30%.
Then, proportion of CA will be =1-p , as sum of proportion is always 1.
So, 2.6p+6.8(1-p)=5.4 , by solving it we get, p=1/3=0.33, i.e in percentage it is 33.33% .
But in option appropriate answer will be 30%.
Anoms said:
6 years ago
(coarse -Combine)/(Combine-Fine) * 100.
So, (6.8-5.4)/(5.4-2.6)*100 = 50%.
So, (6.8-5.4)/(5.4-2.6)*100 = 50%.
Anand Ratan said:
6 years ago
X = course aggregates.
Y = fine aggregates.
Z = combined aggregates.
Formula ,
Fine modules ( % )= ( x - z / z - y ) x 100
=( 6.8 - 5.4 / 5.2 - 2.6 ) x 100
= 50%
Correct answer is C .
Y = fine aggregates.
Z = combined aggregates.
Formula ,
Fine modules ( % )= ( x - z / z - y ) x 100
=( 6.8 - 5.4 / 5.2 - 2.6 ) x 100
= 50%
Correct answer is C .
Khongthaw said:
5 years ago
Let Fine aggregates be P1.
Course aggregates be P2.
Combined aggregates be P.
Given: P1=2.6, P2=6.8 and P=5.4.
Fineness modulus = (P2 - P/P-P1) * 100.
= 50%.
Course aggregates be P2.
Combined aggregates be P.
Given: P1=2.6, P2=6.8 and P=5.4.
Fineness modulus = (P2 - P/P-P1) * 100.
= 50%.
(2)
Rahul said:
5 years ago
@Mrityunjoy mete.
First, find the percentage of fine aggregate by FMc-FMcom/FMcm-FMf.
Then the percentage of coarse aggregate will be 100- the percentage of fine aggregate.
First, find the percentage of fine aggregate by FMc-FMcom/FMcm-FMf.
Then the percentage of coarse aggregate will be 100- the percentage of fine aggregate.
Dawood khan said:
5 years ago
5O is the correct answer.
FM= x-z/z-y x100.
X= coarse agg which is 6.8.
Y = fine agg which is 2.6.
Z= combined or obtained agg which is= 5.4.
Now put the values in the above formula,
= 6.8-5.4/5.4-2.6x100.
=1.4/2.8x100,
= 0.5x100,
= 50.
FM= x-z/z-y x100.
X= coarse agg which is 6.8.
Y = fine agg which is 2.6.
Z= combined or obtained agg which is= 5.4.
Now put the values in the above formula,
= 6.8-5.4/5.4-2.6x100.
=1.4/2.8x100,
= 0.5x100,
= 50.
(5)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers