Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 23)
23.
A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?
Answer: Option
Explanation:
| 2(A + B + C)'s 1 day's work = |  |
1 | + | 1 | + | 1 |  |
= | 15 | = | 1 | . |
| 30 | 24 | 20 | 120 | 8 |
| Therefore, (A + B + C)'s 1 day's work = | 1 | = | 1 | . |
| 2 x 8 | 16 |
| Work done by A, B, C in 10 days = | 10 | = | 5 | . |
| 16 | 8 |
| Remaining work = | |
1 - | 5 | |
= | 3 | . |
| 8 | 8 |
| A's 1 day's work = | |
1 | - | 1 | |
= | 1 | . |
| 16 | 24 | 48 |
| Now, | 1 | work is done by A in 1 day. |
| 48 |
| So, | 3 | work will be done by A in | |
48 x | 3 | |
= 18 days. |
| 8 | 8 |
Discussion:
61 comments Page 6 of 7.
Vipin said:
9 years ago
@Bikash.
Brilliant way, keep it up.
Brilliant way, keep it up.
VIGNESH said:
8 years ago
Super explanations, thanks @nikhil.
Devi said:
8 years ago
Can anyone, please explain easily?
Lalitha said:
1 decade ago
Wow can we take 1/24 (1/16-1/24) ?
Ricky nahar said:
7 years ago
Thanks to all for explaining this.
Aditya said:
1 decade ago
Why we added 2 in the beginning?
(1)
AKSHAY said:
7 years ago
Thanks for the answer @Nikhil.
(1)
Nandhakumar said:
1 decade ago
how to find A's 1's day work
(1)
Vanmathi said:
1 decade ago
How we wrote the third step?
Tanvir said:
5 years ago
How you got A's 1 day work?
(1)
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