Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 23)
23.
A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?
18 days
24 days
30 days
36 days
Answer: Option
Explanation:

2(A + B + C)'s 1 day's work = ( 1 + 1 + 1 ) = 15 = 1 .
30 24 20 120 8

Therefore, (A + B + C)'s 1 day's work = 1 = 1 .
2 x 8 16

Work done by A, B, C in 10 days = 10 = 5 .
16 8

Remaining work = ( 1 - 5 ) = 3 .
8 8

A's 1 day's work = ( 1 - 1 ) = 1 .
16 24 48

Now, 1 work is done by A in 1 day.
48

So, 3 work will be done by A in ( 48 x 3 ) = 18 days.
8 8

Discussion:
61 comments Page 5 of 7.

Amar said:   9 years ago
From where do we get 120?

Can anyone explain?

Archana said:   5 years ago
@Nikhil.

Veery good explanation. Thanks.
(1)

Kishore said:   1 decade ago
Why shld we consider 2(a+b+c) at first ?

Shweta said:   6 years ago
Thank You @Sikandar for A's 1 days work.

Rahul R said:   9 years ago
Thanks, @Nikhil. It's very useful to me.

Damien said:   8 years ago
@Amar.

120 is the LCM of 30, 24 and 20.

Suman sourav said:   9 years ago
@Kishore.

(a+b + b+c + c=a) = 2(a+b+c).

Dibakar De said:   9 years ago
Very clear explanation. Thanks, @Nikhil.

Pari said:   10 years ago
Why we take 1/24, from where its comes?

Maruf Hossain said:   8 years ago
Awesome explanation, Thanks @Nikhil.


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