Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 6 of 7.
Ranjit said:
8 years ago
X/18 +10/15 =1.
X+12 = 18,
X = 18 - 12,
= 6 days.
X+12 = 18,
X = 18 - 12,
= 6 days.
Raja said:
1 decade ago
LCM 90 brief explain?
Left the job B what mean?
Left the job B what mean?
Kamu said:
6 years ago
Can't get it. Please explain me clearly.
Kusum said:
1 decade ago
Can anyone explain this 1/3*18 ? please.
Mehru Qamar said:
4 years ago
Thank you @Shashidhar B Challamarada.
(2)
Sayali said:
1 decade ago
@Rucha.
How you calculate that rate?
How you calculate that rate?
Arsh said:
10 years ago
{(1/15)*10}+{(1/18)*x} = 1.
x = 6.
x = 6.
Santhiya' said:
8 years ago
Good explanation. Thank you all.
Gobinath b said:
1 decade ago
Anyone can you how it is?
Sowndarya said:
9 years ago
Simple & super @Arsh.
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