Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
B's 10 day's work = | ![]() |
1 | x 10 | ![]() |
= | 2 | . |
15 | 3 |
Remaining work = | ![]() |
1 - | 2 | ![]() |
= | 1 | . |
3 | 3 |
Now, | 1 | work is done by A in 1 day. |
18 |
![]() |
1 | work is done by A in | ![]() |
18 x | 1 | ![]() |
= 6 days. |
3 | 3 |
Discussion:
63 comments Page 7 of 7.
Harsha said:
5 years ago
Nice, Thanks @Siva.
Malliga said:
1 decade ago
I can't understand.
Gayu said:
1 decade ago
Superb siva.
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