Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 3 of 7.
Moni said:
9 years ago
A can do a work in P days and B can do the same work in 2P days, A stop working after some days B alone complete the work in R days. How many days it takes to complete the work?
Can anyone solve this problem?
Can anyone solve this problem?
Anusha said:
1 decade ago
A's 1day work = 1/18
B's 1 day work =1/15
but B left the job after 10 days so it is = 10/15
let no of days A alone should work be x
10/15+x/18=1
x/18=1-10/15
x/18=5/15
x/18=1/3
cross mulitiply
x=18/3
x=6
B's 1 day work =1/15
but B left the job after 10 days so it is = 10/15
let no of days A alone should work be x
10/15+x/18=1
x/18=1-10/15
x/18=5/15
x/18=1/3
cross mulitiply
x=18/3
x=6
Uday Bundele said:
2 years ago
A = 18 Day's.
B = 15 Day's.
The LCM is 90.
Easy and short trick.
Before are indicate (+) sing.
After are indicate (-) sing.
So according to question B left work after 10 day's.
90-10(6)/5 ans = 6.
B = 15 Day's.
The LCM is 90.
Easy and short trick.
Before are indicate (+) sing.
After are indicate (-) sing.
So according to question B left work after 10 day's.
90-10(6)/5 ans = 6.
(13)
Iqbal said:
6 years ago
TAKE LCM of 18 & 90 and divide by the days
5-A-18.
6-B-15.
First B do work for 10 days, means 10*6 = 60 already done left work(30) is done by A alone so divide 30/5=6.
And 6 is the answer
5-A-18.
6-B-15.
First B do work for 10 days, means 10*6 = 60 already done left work(30) is done by A alone so divide 30/5=6.
And 6 is the answer
Yakub said:
5 years ago
B one day's work = 1/15
A one day's work = 1/18
B ten day's work = 10/15 = 2/3
Remaining work = 1-2/3 = 1/3
A 's 1/18th work = 1day
A's1/3rd work = 1/3 ÷ 1/18 = 1/3 * 18/1 = 6days.
A one day's work = 1/18
B ten day's work = 10/15 = 2/3
Remaining work = 1-2/3 = 1/3
A 's 1/18th work = 1day
A's1/3rd work = 1/3 ÷ 1/18 = 1/3 * 18/1 = 6days.
(2)
Ruchi Jain said:
1 decade ago
Well the way I solve this question,
REMAINING IS 30 which is to be done by A and A's rate is 5 30/5 = 6.
A B B
T 18 15 10
R 5 6 6
W 90 90 60
REMAINING IS 30 which is to be done by A and A's rate is 5 30/5 = 6.
Kullu sandhu fdk punjab said:
10 years ago
Hi friend see here:
{Time taken to complete work = Left work*Time taken to complete full work}.
Left work 1/3.
Time taken to complete full work by a = 8 then 1/3*8 = 6 answer.
{Time taken to complete work = Left work*Time taken to complete full work}.
Left work 1/3.
Time taken to complete full work by a = 8 then 1/3*8 = 6 answer.
SHRAVAN LAL said:
10 years ago
A ----- 18 days * 5
B ----- 15 days * 6
L.C.M = 90.
B work 10 days and does 10*6 = 60 works.
So left work is 90 - 60 = 30.
A alone does this 30/5 = 6 days.
Very simple.
B ----- 15 days * 6
L.C.M = 90.
B work 10 days and does 10*6 = 60 works.
So left work is 90 - 60 = 30.
A alone does this 30/5 = 6 days.
Very simple.
Mudasir Ali said:
10 years ago
Let total work be x. A completes in 15 days i.e in 15 days:
x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15 = x.
In each day A does x/15 of work.
x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15+x/15 = x.
In each day A does x/15 of work.
Shehnaz khatun said:
9 years ago
B + S can do 1 work in 8 days.
B alone can do 1 work in 12 days .
If B alone worked for 4 days and stopped to do. How long will S take to do the remaining work?
B alone can do 1 work in 12 days .
If B alone worked for 4 days and stopped to do. How long will S take to do the remaining work?
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