Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
10 | 2 |
Solving these two equations, we get : x = | 1 | and y = | 1 | . |
100 | 200 |
(15 men + 20 boy)'s 1 day's work = | ![]() |
15 | + | 20 | ![]() |
= | 1 | . |
100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 9 of 21.
Anamika said:
9 years ago
Hi everyone I didn't understand this.
So please anyone explain it step by step for me.
So please anyone explain it step by step for me.
NIRJARA said:
9 years ago
Thanks a lot @Siddhu.
Gourav Singh said:
9 years ago
14 * 10/35 = 4days
8 + 6 = 14.
8 + 6 = 14.
Nagendran Periyasamy said:
9 years ago
Can anyone explain that 1/100 and 2/200?
Sachin said:
9 years ago
Why it takes 1/10 and 1/2 respectively? Please explain me.
Alia said:
9 years ago
@Atul1487.
Your method was awesome! I liked it well, thanks for that.
Your method was awesome! I liked it well, thanks for that.
Jacqueline said:
9 years ago
@Pravas.
How did you get 8m=16b/ I did not understand please can you explain it clearly?
Thanks.
How did you get 8m=16b/ I did not understand please can you explain it clearly?
Thanks.
Ash said:
9 years ago
I am not getting the solution.
Will anyone solve the equation for me?
Will anyone solve the equation for me?
Bhagi said:
9 years ago
Can anyone tell formula for this question?
Deepika said:
9 years ago
Thanks @Pravas.
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