Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 21 of 21.
Meera said:
1 decade ago
Hi Sangeetha its very easy to solve this equations.
6x+8y=1/10 ----- (i)
26x+48y=1/2 ------(ii)
Multiply 1st equation into 6, then we get:
36x+48y=1/10*6
26x+48y=1/2
Change the sign of 2nd equation
36x+48y=3/5
-26x-48y=-1/2
The result is
10x=3/5-1/2
10x=1/10
x=1/100
Then apply x value into 1st equation
6x+8y=1/10
6*1/10+8y=1/10
8y=4/100
y=1/200
Thats it.
6x+8y=1/10 ----- (i)
26x+48y=1/2 ------(ii)
Multiply 1st equation into 6, then we get:
36x+48y=1/10*6
26x+48y=1/2
Change the sign of 2nd equation
36x+48y=3/5
-26x-48y=-1/2
The result is
10x=3/5-1/2
10x=1/10
x=1/100
Then apply x value into 1st equation
6x+8y=1/10
6*1/10+8y=1/10
8y=4/100
y=1/200
Thats it.
(3)
Sangeetha said:
2 decades ago
Can you please solve these 2 equations and show me the result?
(1)
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