# Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 6)

6.

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

Answer: Option

Explanation:

Let 1 man's 1 day's work = *x* and 1 boy's 1 day's work = *y*.

Then, 6x + 8y = |
1 | and 26x + 48y = |
1 | . |

10 | 2 |

Solving these two equations, we get : x = |
1 | and y = |
1 | . |

100 | 200 |

(15 men + 20 boy)'s 1 day's work = | 15 | + | 20 | = | 1 | . | ||

100 | 200 | 4 |

15 men and 20 boys can do the work in 4 days.

Discussion:

193 comments Page 1 of 20.
Sangeetha said:
1 decade ago

Can you please solve these 2 equations and show me the result?

(1)

Meera said:
1 decade ago

Hi Sangeetha its very easy to solve this equations.

6x+8y=1/10 ----- (i)

26x+48y=1/2 ------(ii)

Multiply 1st equation into 6, then we get:

36x+48y=1/10*6

26x+48y=1/2

Change the sign of 2nd equation

36x+48y=3/5

-26x-48y=-1/2

The result is

10x=3/5-1/2

10x=1/10

x=1/100

Then apply x value into 1st equation

6x+8y=1/10

6*1/10+8y=1/10

8y=4/100

y=1/200

Thats it.

6x+8y=1/10 ----- (i)

26x+48y=1/2 ------(ii)

Multiply 1st equation into 6, then we get:

36x+48y=1/10*6

26x+48y=1/2

Change the sign of 2nd equation

36x+48y=3/5

-26x-48y=-1/2

The result is

10x=3/5-1/2

10x=1/10

x=1/100

Then apply x value into 1st equation

6x+8y=1/10

6*1/10+8y=1/10

8y=4/100

y=1/200

Thats it.

(2)

Siddharth said:
1 decade ago

No need to solve equation:

we have

6x+8y=1/10 ----- (1)

26x+48y=1/2 ------(2)

we want to find: 15x+20y=?----(3)

now taking 2 common form equ(1),

we get:

2(3x+4y)=1/10

So we have, 3x+4y=1/20...ok...

now

in equ 3, take 5 common;

we get:

=5(3x+4y) (3x+4y=1/20)

=5*(1/20)

=4 (ans)

we have

6x+8y=1/10 ----- (1)

26x+48y=1/2 ------(2)

we want to find: 15x+20y=?----(3)

now taking 2 common form equ(1),

we get:

2(3x+4y)=1/10

So we have, 3x+4y=1/20...ok...

now

in equ 3, take 5 common;

we get:

=5(3x+4y) (3x+4y=1/20)

=5*(1/20)

=4 (ans)

(4)

Singh said:
1 decade ago

Siddu you are genious friend.

Arun said:
1 decade ago

There must be a faster way of doing this mentally. Like skipping the equation part. Some kind of approximation. Does anyone know?

Bharathi said:
1 decade ago

How 1/100+1/200=4 ?

Nagarjun said:
1 decade ago

@Bharathi.

Hey its not 1/100+1/200=4

Its (15/100)+(20/100)

This vl give 1/4, vch is 1 day's work, and finally they can complete it in 4 days.

Hey its not 1/100+1/200=4

Its (15/100)+(20/100)

This vl give 1/4, vch is 1 day's work, and finally they can complete it in 4 days.

Jyothi said:
1 decade ago

Hi siddu.

I'm jyothi. You are genious. Thanks friend.

I'm jyothi. You are genious. Thanks friend.

(1)

Vicky said:
1 decade ago

@Sidhu

We want to find: 15x+20y=?----(3)

now taking 2 common form equ(1),

We get: 2(3x+4y)=1/10

So we have, 3x+4y=1/20...ok...///// if we take 2 common ok

2(3x+4y)ok but how u get = 1/20 hmmmmmm

We want to find: 15x+20y=?----(3)

now taking 2 common form equ(1),

We get: 2(3x+4y)=1/10

So we have, 3x+4y=1/20...ok...///// if we take 2 common ok

2(3x+4y)ok but how u get = 1/20 hmmmmmm

Vicky said:
1 decade ago

2x+3y=1/10 ----- (1)

3x+2y=1/8 ------(2)

we want to find: 2x+1y=?----(3)

any one can solve this

3x+2y=1/8 ------(2)

we want to find: 2x+1y=?----(3)

any one can solve this

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