Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
| Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = |  |
15 | + | 20 |  |
= | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
201 comments Page 21 of 21.
ESNALA SIDDA said:
1 week ago
2(3m+4b) = 1/10,
3m+4b = 1/20,
5(3m+5b) = ?
= 5×1/20,
= 1/4,
= 4days.
3m+4b = 1/20,
5(3m+5b) = ?
= 5×1/20,
= 1/4,
= 4days.
(6)
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