Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
4 days
5 days
6 days
7 days
Answer: Option
Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2

Solving these two equations, we get : x = 1 and y = 1 .
100 200

(15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 .
100 200 4

15 men and 20 boys can do the work in 4 days.

Discussion:
201 comments Page 2 of 21.

Chetan said:   1 decade ago
Proceed the same way as Meera has done it for Sangeeta.

Richa said:   1 decade ago
Hi siddhu! thanks friend.

Manav said:   1 decade ago
@ vicky

2(3x+4y)= 1/10

now, take that 2 to the other side of the eqn, we get

3x+4y= 1/20

Himadri said:   1 decade ago
This is also easy way friends...
6x+8y=1/10
2(3x+4y)=1/10
3x+4y=1/20
both side multiple with 5
15x+20y=1/4
so 1/4 work complete =1 day
total work=4days

Pradeep kumar said:   1 decade ago
The solution is being given by you is 100 % satisfying. Thanks to all.

Subrata Dev said:   1 decade ago
Excellent solving. Thanks for nice math solving.

Thanks

Rupali said:   1 decade ago
Thank you siddharth. The most simple way to explain the method. :-).

Chandra said:   1 decade ago
So we have, 3x+4y=1/20...ok...
now
in equ 3, take 5 common;
we get:
=5(3x+4y) (3x+4y=1/20)----->//siddu can u explain me this step.
=5*(1/20)
=4 (ans)

Rithesh said:   1 decade ago
Siddu I am impressed I hope you continue giving answer like that.

Ragavi said:   1 decade ago
Siddu you are excellent. Please keep help us with your short cutz:).


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